我正在尝试创建一个程序,使用C在后缀表示法中运行计算,并从unix命令行读取值。但是,我对C语言很陌生,并且在使事情正常工作方面遇到了一些麻烦。我正在读取NULL和分段错误的读数,但我不确定unix命令行中的调试是如何工作的,所以我无法告诉你我在哪里得到错误。对此事我感激不尽。
#include <stdio.h>
double stack(int argc, char* argv[]);
int main(int argc, char* argv[]) {
double result;
result = stack(argc, argv);
printf("%s\n", result);
}
-
#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
static double stck[100];
static int top = 0;
/*Push Function*/
static void push( double v){
stck[top] = v; /* Places the value at the current top position of the stack */
top++; /* Increases the top position of the stack */
printf("%s\n", top);
}
/*Pop Function*/
static double pop() {
double ret;
ret = stck[top]; /* Stores the value of the top position in the stack to ret */
top--; /* Decreases the top position of the stack */
printf("%s\n", top);
return ret; /* Returns the value of ret */
}
double stack(int argc, char* argv[]){
double h; /* Placeholder Variable for the result of the mathematic equations during the loop */
int i;
for (i = 0; i <= argc - 1; i++) { /* Loops to read in all values, barring the first, for argv */
if (strcmp(argv[i], "*") == 0) {
double a = pop(); /* Pulls in the top value of the stack */
double b = pop(); /* Pulls in the next top value of the stack*/
h = b*a; /* Performs the multiplication of the two stack values */
push(h); /* Returns the result to the top of the stack */
} else if (strcmp(argv[i], "+") == 0) {
printf("%s\n", "Made it here plus \0");
double a = pop(); /* Pulls in the top value of the stack */
double b = pop(); /* Pulls in the next top value of the stack*/
h = b+a; /* Performs the multiplication of the two stack values */
push(h); /* Returns the result to the top of the stack */
} else if (strcmp(argv[i], "/") == 0) {
double a = pop(); /* Pulls in the top value of the stack */
double b = pop(); /* Pulls in the next top value of the stack*/
h = b/a; /* Performs the division of the two stack values */
push(h); /* Returns the result to the top of the stack */
} else if (strcmp(argv[i], "^") == 0) {
double a = pop(); /* Pulls in the top value of the stack */
double b = pop(); /* Pulls in the next top value of the stack*/
h = pow(b,a); /* Raises the number b by the number a power */
push(h); /* Returns the result to the top of the stack */
} else if (strcmp(argv[i], "-") == 0) {
double a = pop(); /* Pulls in the top value of the stack */
double b = pop(); /* Pulls in the next top value of the stack*/
h = b-a; /* Performs the subtraction of the two stack values */
push(h); /* Returns the result to the top of the stack */
} else {
printf("%s\n", "Made it here \0");
double ph;
ph = (double)atof(argv[i]);
printf("%s\n", ph);
push(ph); /* Places the current value of argv[i] on the top of the stack */
}
}
return stck[0]; /* Returns the final result of the calculation to main.c */
}
答案 0 :(得分:1)
printf()
格式说明符%s
需要character array
的参数。但此处top
为integer
,因此您需要使用%d
格式说明符。
全部改变
printf("%s\n", top); ==> printf("%d\n", top);
^ ^
答案 1 :(得分:1)
您的推送和弹出操作需要完全相反。
所以如果推送
stackarray[index] = v
index++ //increment last
pop必须
index-- //decrement first
return stackarray[index]
否则,pop将始终在最近推送的值之后从一个插槽返回值。
调试使用命令行参数的程序与调试任何其他程序没有太大区别。但您可能需要阅读调试器的文档以了解如何将参数传递给程序。在gdb中:
gdb> break main
gdb> run arg1 arg2 arg3 ...
也就是说,将参数添加到run
行,就像run
是程序的名称一样。
答案 2 :(得分:0)
检查所有printf以确保格式说明符与参数匹配。