我是学生,这是一项任务。我按照这个程序的指示,但是当我运行我的应用程序时,它崩溃了。基于堆栈跟踪我相信问题出在Intent上。但我不确定。有人可以检查我的代码并解释错误和原因。
调用其他活动的主要活动
package edu.cvtc.android.activitylab;
import android.os.Bundle;
import android.app.Activity;
import android.content.Intent;
import android.view.Menu;
import android.view.View;
import android.view.View.OnClickListener;
public class EnterNameActivity extends Activity implements OnClickListener{
android.widget.EditText nameField;
android.widget.Button okButton;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.name_getter);
//EditText nameField = (EditText) findViewById(R.id.editText1);
this.nameField.findViewById(R.id.editText1);
//Button okButton = (Button) findViewById(R.id.button1);
this.okButton.findViewById(R.id.button1);
//EditText and Button are used to type cast the variables because
//findViewById only returns an object.
okButton.setOnClickListener(this);
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.menu_entername, menu);
return true;
}
@Override
public void onClick(View v) {
// Get the text value the user entered
String tempText = nameField.getText().toString();
//Clear the text field if there is data
if(tempText != ""){
nameField.setText("");
}
//Create an Intent to call another activity
Intent myIntent = new Intent(this, LayoutMainActivity.class);
//Passing the user entered name to the main greeting activity
myIntent.putExtra("name", tempText);
this.startActivity(myIntent);
}
}
其他活动
package edu.cvtc.android.activitylab;
import android.os.Bundle;
import android.app.Activity;
import android.view.Menu;
import android.widget.TextView;
public class LayoutMainActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.layout_main);
android.os.Bundle temp = this.getIntent().getExtras();
if(temp != null){
//Extract the username from the bundle
String userName = temp.getString("name");
//get the TextView Id to change the text
TextView text = (TextView) findViewById(R.id.textView1);
text.setText("Hello " + userName);
}
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.menu_layout_main, menu);
return true;
}
}
清单
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="edu.cvtc.android.activitylab"
android:versionCode="1"
android:versionName="1.0" >
<uses-sdk
android:minSdkVersion="10"
android:targetSdkVersion="18" />
<application
android:allowBackup="true"
android:icon="@drawable/ic_launcher"
android:label="@string/app_name"
android:theme="@style/AppTheme" >
<activity
android:name="edu.cvtc.android.activitylab.LayoutMainActivity"
android:label="@string/app_name" >
</activity>
<activity
android:name="edu.cvtc.android.activitylab.EnterNameActivity"
android:label="@string/title_activity_enter_name" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
</manifest>
来自调试的堆栈跟踪
Thread [<1> main] (Suspended (exception RuntimeException))
<VM does not provide monitor information>
ActivityThread.handleLaunchActivity(ActivityThread$ActivityClientRecord, Intent) line: 2261
ActivityThread.access$600(ActivityThread, ActivityThread$ActivityClientRecord, Intent) line: 141
ActivityThread$H.handleMessage(Message) line: 1256
ActivityThread$H(Handler).dispatchMessage(Message) line: 99
Looper.loop() line: 137
ActivityThread.main(String[]) line: 5103
Method.invokeNative(Object, Object[], Class, Class[], Class, int, boolean) line: not available [native method]
Method.invoke(Object, Object...) line: 525
ZygoteInit$MethodAndArgsCaller.run() line: 737
ZygoteInit.main(String[]) line: 553
如果您需要任何其他XML文件,请告诉我们。
答案 0 :(得分:1)
我想你在做什么是错的:
//EditText nameField = (EditText) findViewById(R.id.editText1);
this.nameField.findViewById(R.id.editText1);
//Button okButton = (Button) findViewById(R.id.button1);
this.okButton.findViewById(R.id.button1);
//EditText and Button are used to type cast the variables because
//findViewById only returns an object.
只需替换:
this.nameField.findViewById(R.id.editText1);
和
this.okButton.findViewById(R.id.button1);
人:
nameField = (EditText) findViewById(R.id.editText1);
和
okButton = (Button) findViewById(R.id.button1);
希望这有帮助。
答案 1 :(得分:1)
您没有提供完整的堆栈跟踪,因此很难准确说出导致您出现第一个错误的原因,但此处存在许多问题。我将在代码中提供一些希望有用的评论。
首先,你几乎已经初步确定了View
,但是你改变了它们。从
onCreate()
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.name_getter);
//EditText nameField = (EditText) findViewById(R.id.editText1);
this.nameField.findViewById(R.id.editText1); // this returns an EditText object so it isn't being applied to a variable.
//Button okButton = (Button) findViewById(R.id.button1);
this.okButton.findViewById(R.id.button1);
//EditText and Button are used to type cast the variables because
//findViewById only returns an object.
okButton.setOnClickListener(this);
}
到
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.name_getter);
EditText nameField = (EditText) findViewById(R.id.editText1);
Button okButton = (Button) findViewById(R.id.button1);
okButton.setOnClickListener(this);
}
同时更改<{1}}的初始化,以通过更改
来使用Intent
Activty
Context
到
//Create an Intent to call another activity
Intent myIntent = new Intent(this, LayoutMainActivity.class);
这是另一个问题
//Create an Intent to call another activity
Intent myIntent = new Intent(EnterNameActivity .this, LayoutMainActivity.class);
当你用这种方式比较if(tempText != ""){
时,你要比较对象是否相等而不是它们所引用的对象。它应该是
String
如果空if(!"".equals(tempText)){
不等于String
的值,则说明。或者你可能会看到
tempText
但第一种方法可以防范if (!tempText.equals("")){
,因为如果NPE
为tempText
,您将以第二种方式获得null
,因为您将调用函数一个NPE
答案 2 :(得分:0)
EditText nameField = (EditText) findViewById(R.id.editText1);
Button okButton = (Button) findViewById(R.id.button1);
//EditText and Button are used to type cast the variables because
//findViewById only returns an object.
okButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View arg0) {
// Get the text value the user entered
String tempText = nameField.getText().toString();
//Clear the text field if there is data
if(tempText != ""){
nameField.setText("");
}
//Create an Intent to call another activity
Intent myIntent = new Intent(EnterNameActivity.this, LayoutMainActivity.class);
//Passing the user entered name to the main greeting activity
myIntent.putExtra("name", tempText);
startActivity(myIntent);
}
这是处理edittexts,按钮和onClicks的更好方法。
*从活动中删除onClick,并删除onclick方法和按钮以及您使用此方法的edittext导入方法。
答案 3 :(得分:0)
试试这种方式
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.layout_main);
//Extract the username from the bundle
String userName = getIntent().getStringExtra("name"); // UPDATE HERE
//get the TextView Id to change the text
TextView text = (TextView) findViewById(R.id.textView1);
text.setText("Hello " + userName!=null?userName:""); // UPDATE HERE
}