我正在尝试在文本框中输入一个值并让它触发数据库的更新语句,但帖子.val()
返回一个空值。
这是功能:
<script src="http://code.jquery.com/jquery-1.10.1.min.js"></script>
<script>
function save_a9(id) {
$.post('response6.php', {starID:id, starURL: $('#starurl').val()},
function(result) {
alert(result);
window.location.reload();
});
}
</script>
这是按钮和文本框:
echo "<br><b>request to join site: {$row9['count']}</b><br>";
while ($row99 = $prep99->fetch(PDO::FETCH_ASSOC)) {
echo "{$row99['starID']} , {$row99['starName']} = {$row99['twitter']}";
if ($row99['guest'] == 0) {
$guest = 'ongoing';
};
if ($row99['guest'] == 1) {
$guest = 'guest';
};
if ($row99['guest'] == 2) {
$guest = 'PLEASE SELECT ONE';
};
echo " ~ $guest ~ <br>";
echo "<input type='text' name='starurl' value='{$row99['starURL']}' id='starurl' style='width:100px; height:30px;'/>";
echo "<br><button onclick='save_a9({$row99['starID']})'>Approve</button><button onclick='save_d9({$row99['starID']})'>Disapprove</button><br>";
}
这是response6.php:
<?php
include("db_conn.php");
$sql = "update stars set approved = 1, starURL = ? where starID = ?";
$qc = $pdo_conn->prepare($sql);
$qc->execute(array($_POST['starURL'], $_POST['starID']));
echo 'saved';
?>
答案 0 :(得分:1)