@Entity
@Table(name="dt_user" , uniqueConstraints = {@UniqueConstraint(columnNames="user_no"), @UniqueConstraint(columnNames="account")}
)
public class User implements java.io.Serializable {
/**
*
*/
private static final long serialVersionUID = -8149578944942492965L;
// Fields
private long id;
private String userNo;
private Set<UserRelative> userRelatives = new HashSet<UserRelative>(0);
// Constructors
/** default constructor */
public User() {
}
@OneToMany(cascade=CascadeType.ALL, fetch=FetchType.LAZY, mappedBy="user")
public Set<UserRelative> getUserRelatives() {
return this.userRelatives;
}
}
以上是用户实体;下面是另一个UserRelative实体:当想要getUserRelatives()时,问题就发生了。
@Entity
@Table(name="dt_user_relative")
public class UserRelative implements java.io.Serializable {
/**
*
*/
private static final long serialVersionUID = 5035928604641787267L;
// Fields
private long id;
private User user;
.....
@Id @GeneratedValue(strategy=IDENTITY)
@Column(name="id", unique=true, nullable=false)
public long getId() {
return this.id;
}
public void setId(long id) {
this.id = id;
}
@ManyToOne(fetch=FetchType.LAZY)
@JoinColumn(name="user_id")
public User getUser() {
return this.user;
}
public void setUser(User user) {
this.user = user;
}
.....
}
我的问题是当我执行此代码时发生错误:如何通过userNo获取getRelativeTickets()?
userDAO.getUserByNo("10001148").getRelativeTickets().size();
public User getUserByNo(String userNo) {
// TODO Auto-generated method stub
String query = "from User t where t.userNo=?1";
List<User> ls = this.findByQuery(query, userNo);
if (ls.size() > 0)
return ls.get(0);
return null;
}
答案 0 :(得分:5)
它没有懒惰地初始化集合,因为Hibernate会话在getUserByNo
方法结束时关闭 - 数据库连接不再可用,并且对象图被分离。现在,当您调用getRelativeTickets()
方法时,Hibernate无法获取关联,因为会话不再可用,并且Hibernate不会隐式地打开新连接(或会话)来延迟加载关联。
建议的解决方案是确保在从User
方法返回之前完全初始化getUserByNo
所需的所有关联。在HQL中,您可以指定使用from
子句fetch join
来急切地获取关联:
String query = "from User t left join fetch t.relativeTickets where t.userNo=?1";
这将返回完全初始化User
关联的relativeTickets
。这样,关联的初始化发生在单个SQL语句中,因此不需要再次命中DB来初始化关联。