为什么这个Javascript没有添加HTML

时间:2013-09-09 23:49:09

标签: javascript jquery html css

此脚本将创建一个新元素并为其提供正确的ID,但不会加载到下面的HTML /字符串中:

<script>
$(function () {
    $("#test img").on("click", function (e) {
        var titleEl = document.createElement("div");
        var laptopImg = $("#test img");
        var theText = "<p>this is a test</p>"
        document.body.appendChild(titleEl);
        titleEl.id = "img-title";
        titleEl.html = theText;
        titleEl.position = laptopImg.position;
    });
});
</script>
<style>
#img-title {
    color:black;
    z-index:1;
}
#test img {
    position: absolute;
    transform: scale(1,1);
    -moz-transition-duration: 2s;
}
#test img:hover {
    transform: scale(.5,.5);
    -moz-transition-duration: 2s;
}
#test img:active {
    -moz-transform:skew(360);
    -moz-transition-duration: 2s;
}
</style>
<div id="test">
    <%= image_tag('test_2.jpg') %>
</div>

我尝试了各种功能,例如.val .appendChild,等等......但似乎没有任何功能。它只是在我每次点击图像时创建一个新的空div。

2 个答案:

答案 0 :(得分:2)

作为原始解决方案,您需要使用innerHTML

$(function() { 
    $("#test img").on("click", function(e) {

        var titleEl = document.createElement("div");
        var laptopImg = $("#test img");
        var theText = "<p>this is a test</p>"
        document.body.appendChild(titleEl);
        titleEl.id = "img-title";
        titleEl.innerHTML = theText ;
        titleEl.style.position = laptopImg.css('position'); 

    });

});

演示:Fiddle

jQuery-ish解决方案

$(function () {
    var $laptopImg = $("#test img").on("click", function (e) {
        var theText = "<p>this is a test</p>"
        $div = $('<div />', {
            id: 'img-title',
            position: $laptopImg.css('position'),
            html: theText
        }).appendTo('body')
    });
});

演示:Fiddle

注意:如果完成多次点击,还需要确保没有重复的ID

答案 1 :(得分:0)

此代码段应为您添加div

$(function() { 
    $("#test img").on("click", function(e) {
        var laptopImg = $("#test img");

        $('<div id="img-title"><p>this is a test</p></div>')
            .appendTo(document.body)
            .css('position', 'absolute')
            .offset(laptopImg.offset());
    });
});