Question

我尝试从表CODE加载NAME_IMAGE和IMAGES作为最终jpg的名称...但我不知道如何使用每张图片他的名字和代码......你有什么想法吗？

SqlConnection connection = new SqlConnection("*****");
connection.Open();
SqlCommand command = new SqlCommand("SELECT IMAGE,NAME_IMAGE,CODE FROM IMAGES", connection);
byte[] buffer = (byte[]) command.ExecuteScalar ();
connection.Close();
FileStream fs = new FileStream(@"C:\Users\L\Desktop\\" + (CODE) + "_" + (NAME_IMAGE) + ".jpg", FileMode.Create);
fs.Write(buffer, 0, buffer.Length);
fs.Close();

Answer 1

您正在阅读多个列，并且您没有where子句，因此这里的第一个问题是ExecuteScalar - 旨在读取第一行的第一列仅即可。由于这不是这种情况，您应该查看ExecuteReader。或者包装读者的工具，例如“dapper”：

using(var connection = new SqlConnection("*****"))
{
    var data = connection.Query("SELECT IMAGE,NAME_IMAGE,CODE FROM IMAGES");
    foreach(dynamic row in data)
    {
        byte[] data = row.IMAGE; // yes, as simple as that
        string name = row.NAME_IMAGE;
        //... do something with data / name
    }
}

或通过原始ADO.NET：

using(var connection = new SqlConnection("*****"))
using(var cmd = connection.CreateCommand())
{
    cmd.CommandText = "SELECT IMAGE,NAME_IMAGE,CODE FROM IMAGES";
    connection.Open();
    using(var reader = cmd.ExecuteReader())
    {
        while(reader.Read())
        {
            byte[] data = (byte[])reader["IMAGE"];
            string name = (string)reader["NAME"];
            // ...
        }
    }
}

SQL Server数据库中的文件名

1 个答案: