创建ctypes
变量时,是否可以使用python变量传递值?
我有一些代码,我在调用共享的C库。如果我使用方法1(参见下文)将参数传递给此C库,则一切正常。但如果我使用方法2,我会得到垃圾。代码还有其他部分。但我已经确认,当我用方法1替换方法2时,事情很有效。所以这里有些不对劲。
如果我在方法2中所做的事情无效,那么如果我想自动化为给定变量的不同值运行代码的过程有什么选择呢?
方法1(效果很好)
import ctypes as C
c_thresholds = (C.c_double * 4)()
for idx, value in enumerate(thresholds):
c_thresholds[idx] = value
goodH = Good(C.c_char('H'), C.c_double(0.5), C.c_int(100), C.c_int(20))
goodL = Good(C.c_char('L'), C.c_double(0.5), C.c_int(75), C.c_int(20))
c_parameters = Params(
var1 = C.c_int(100),
var2 = C.c_int(4),
var3 = C.c_int(5),
var4 = C.c_int(5000),
var5 = C.c_char_p("modelname"),
var6 = C.c_double(0.5),
var7 = C.c_double(90),
var8 = c_thresholds,
var9 = C.c_int(2),
H = goodH,
L = goodL
)
runsimulation(c_parameters)
方法2(这不起作用,输出垃圾)
import ctypes as C
def create_cparams(var1, var2, var3, var4, var5, var6, var7, var8, var9):
c_thresholds = (C.c_double * 4)()
for idx, value in enumerate(var8):
c_thresholds[idx] = value
goodH = Good(C.c_char('H'), C.c_double(0.5), C.c_int(100), C.c_int(20))
goodL = Good(C.c_char('L'), C.c_double(0.5), C.c_int(75), C.c_int(20))
c_parameters = Params(
var1 = C.c_int(var1),
var2 = C.c_int(var2),
var3 = C.c_int(var3),
var4 = C.c_int(var4),
var5 = C.c_char_p(var5),
var6 = C.c_double(var6),
var7 = C.c_double(var7),
var8 = c_thresholds,
var9 = C.c_int(var9),
H = goodH,
L = goodL
)
return c_parameters
# These are python variables
var1 = 100
var2 = 4
var3 = 5
var4 = 5000
var5 = "modelname"
var6 = 0.5
var7 = 90
var8 = [1, 0.9, 0.8, 0.7]
var9 = 2
# Calling the create_cparams function defined above
c_parameters = create_cparams(var1, var2, var3, var4, var5, var6, var7, var8, var9)
runsimulation(c_parameters)
如果它有用,则Params类由(不会改变两种方法)给出:
class Params(C.Structure):
_fields_ = [
("var1", C.c_int),
("var2", C.c_int),
("var3", C.c_int),
("var4", C.c_int),
("var5", C.c_char_p ),
("var6", C.c_double),
("var7", C.c_double),
("var8", (C.c_double * 4) ),
("var9", C.c_int),
("H", Good),
("L", Good)
]
C函数原型
// runsimulation() function above calls this C function
void run_multiple_reps (struct params parameters, struct repdata *data,
int len_timepdsarr, int *timepdsarr)
// params struct on C side, which Params class duplicates
struct params
{
int var1;
int var2;
int var3;
int var4;
char *var5;
double var6;
double var7;
double var8[4];
int var9;
struct good H;
struct good L;
};
答案 0 :(得分:1)
Structure
的字段属性是CField
描述符对象。描述符就像Python property
或类似__slots__
属性,如果您熟悉其中任何一个。 CField
知道字段的数据类型及其到缓冲区的偏移量。每个C数据类型都有一个关联的get / set函数,可以转换为Python对象和从Python对象转换。因此,通常可以将Python对象直接分配给该字段。例如:
thresholds = [1, 0.9, 0.8, 0.7]
c_parameters = Params(
var1 = 100,
var2 = 4,
var3 = 5,
var4 = 5000,
var5 = "modelname",
var6 = 0.5,
var7 = 90,
var8 = (C.c_double * 4)(*thresholds),
var9 = 2,
H = Good('H', 0.5, 100, 20),
L = Good('L', 0.5, 75, 20),
)
如果ctypes需要保存对Python对象的引用以使其保持活动状态,则引用将存储在_objects
的{{1}} dict中。在这种情况下,例如Structure
中的数组只是复制到缓冲区中,因此var8
不需要保存对原始数据的引用。