我有一个相当简单的数据库,只有一个表包含Texas Courts的联系信息。搜索表单允许用户选择该类型的法院,然后输入他们希望搜索的城市或县名称(单独的字段)。
代码:
$sql = mysql_query ("SELECT * FROM COURTS
WHERE Type = '$_POST[Type]' AND City LIKE '$_POST[City]'
OR Type = '$_POST[Type]' AND County LIKE '$_POST[County]'
ORDER BY County, City")
or die(mysql_error()); ?>
<table id="customers">
<?php while($rows = mysql_fetch_array($sql)): ?>
<tr class="alt">
<td><?php echo $rows[Court]; ?> <?php echo $rows[Type]; ?><br></td>
<td><?php echo $rows[City]; ?>, <?php echo $rows[State]; ?><br></td>
<td><?php echo "<a href=$rows[URL]>Court Info</a>"; ?><br></td>
</tr>
<?php endwhile; ?>
</table>
当搜索名称与县名不同的城市时(例如,Boerne,Kendall County),当表中只有一个存在时,MySQL会返回该城市的两个结果。第一个返回具有指向当前搜索结果页面的超链接,第二个链接指向正确的信息页面。如果一个城市与该县共享其名称(例如Bandera,Bandera County),则返回是正确的 - 一个具有正确URL的列表。
我尝试过分组,排序和哭泣,但没有任何作用。
编辑:
添加paranthesis仍会产生同样的问题...
$sql = mysql_query ("SELECT * FROM COURTS
WHERE (Type = '$_POST[Type]' AND City LIKE '$_POST[City]')
OR (Type = '$_POST[Type]' AND County LIKE '$_POST[County]')
ORDER BY County, City")
编辑:表格结构......
+--------------+--------------+----------+-----------+---------+-------+-------+---------------+--------------+----------+--------------+
| Type | Court | County | Street | City | State | Zip | Email | Website | Phone | URL |
+--------------+--------------+----------+-----------+---------+-------+-------+---------------+--------------+----------+--------------+
| Justice of.. | Precinct 1.. | Anderson | P O Box.. | Elkhart | TX | 75839 | gthomas@co... | http://www.. | 903-76.. | http://www.. |
+--------------+--------------+----------+-----------+---------+-------+-------+---------------+--------------+----------+--------------+
当城市名称与其郡名称不匹配时的结果:
+-------------------+-------------+------------+
| Boerne Municipal | Boerne, TX | Court Info | <<Court info links to the wrong URL (current page)
+-------------------+-------------+------------+
| Boerne Municipal | Boerne, TX | Court Info | <<Court Info links to correct URL
+-------------------+-------------+------------+
上述结果适用于Boerne市,该市仅有一个市法院条目。
答案 0 :(得分:0)
你需要括号......
$sql = mysql_query ("SELECT * FROM COURTS
WHERE (Type = '$_POST[Type]' AND City LIKE '$_POST[City]')
OR (Type = '$_POST[Type]' AND County LIKE '$_POST[County]')
ORDER BY County, City")