Question

视图

<?php echo $this->Form->create('Practice');
echo $this->Form->input('title',array('value'=>'test value'));
echo $this->Js->submit('Ajax Submit', array(
'update' => '#left',
 'url'=>'/practices/content',
 'async' => true,
 'method' => 'post',
 'dataExpression'=>true,
 'data'=> $this->Js->serializeForm(array(
     'isForm' => true,
     'inline' => true 

  ))
    ));
?> <?php echo $this->Form->end(); ?>

表单在Ajax提交之前正常工作。 ajax submit实际上返回同一模型的新表单字段。下面是首先为ajax

发送表单的视图

echo $this->Form->input('Practice.options',array('value'=>'regex value'));

新字段值未以表单

提交

Answer 1

我做了两个错误，首先是新的ajax返回的字段不在表单标签中，我需要绕过cakephp安全检查

function beforeFilter() {
        parent::beforeFilter();
        $this->Security->blackHoleCallback = 'blackhole';
        $this->Security->csrfCheck = false;
        $this->Security->validatePost = false;
        $this->set('contentLayout', 'admin_dashboard');
    }

Answer 2

确保您在表单末尾放置

<?php echo $this->Form->end(); ?>

然后解锁SecurityComponent的当前操作

JS添加新字段后，cakephp表单未正确提交

2 个答案: