从.NET应用程序捕获控制台输出(C#)

时间:2008-10-09 11:27:15

标签: c# .net debugging console

如何从.NET应用程序调用控制台应用程序并捕获控制台中生成的所有输出?

(请记住,我不想先将信息保存在文件中,然后重新登录,因为我希望将其作为实时信息接收。)

8 个答案:

答案 0 :(得分:148)

使用ProcessStartInfo.RedirectStandardOutput属性可以很容易地实现这一点。完整的样本包含在链接的MSDN文档中;唯一需要注意的是,您可能还需要重定向标准错误流以查看应用程序的所有输出。

Process compiler = new Process();
compiler.StartInfo.FileName = "csc.exe";
compiler.StartInfo.Arguments = "/r:System.dll /out:sample.exe stdstr.cs";
compiler.StartInfo.UseShellExecute = false;
compiler.StartInfo.RedirectStandardOutput = true;
compiler.Start();    

Console.WriteLine(compiler.StandardOutput.ReadToEnd());

compiler.WaitForExit();

答案 1 :(得分:26)

这比@mdb接受的答案有点改进。具体来说,我们还捕获过程的错误输出。此外,我们通过事件捕获这些输出,因为如果要捕获 错误和常规输出,则ReadToEnd()不起作用。我花了很长时间才能完成这项工作,因为它实际上还需要在Start()之后调用BeginxxxReadLine()。

using System.Diagnostics;

Process process = new Process();

void LaunchProcess()
{
    process.EnableRaisingEvents = true;
    process.OutputDataReceived += new System.Diagnostics.DataReceivedEventHandler(process_OutputDataReceived);
    process.ErrorDataReceived += new System.Diagnostics.DataReceivedEventHandler(process_ErrorDataReceived);
    process.Exited += new System.EventHandler(process_Exited);

    process.StartInfo.FileName = "some.exe";
    process.StartInfo.Arguments = "param1 param2"
    process.StartInfo.UseShellExecute = false;
    process.StartInfo.RedirectStandardError = true;
    process.StartInfo.RedirectStandardOutput = true;

    process.Start();
    process.BeginErrorReadLine();
    process.BeginOutputReadLine();          

    //below line is optional if we want a blocking call
    //process.WaitForExit();
}

void process_Exited(object sender, EventArgs e)
{
    Console.WriteLine(string.Format("process exited with code {0}\n", process.ExitCode.ToString()));
}

void process_ErrorDataReceived(object sender, DataReceivedEventArgs e)
{
    Console.WriteLine(e.Data + "\n");
}

void process_OutputDataReceived(object sender, DataReceivedEventArgs e)
{
    Console.WriteLine(e.Data + "\n");
}

答案 2 :(得分:13)

创建控制台进程时,使用ProcessInfo.RedirectStandardOutput重定向输出。

然后您可以使用Process.StandardOutput来读取程序输出。

第二个链接有一个示例代码,如何操作。

答案 3 :(得分:7)

ConsoleAppLauncher是一个专门用来回答这个问题的开源库。它捕获控制台中生成的所有输出,并提供启动和关闭控制台应用程序的简单界面。

每次控制台将新行写入标准/错误输出时,都会触发ConsoleOutput事件。这些行排队并保证遵循输出顺序。

也可以NuGet package

获取完整控制台输出的示例调用:

// Run simplest shell command and return its output.
public static string GetWindowsVersion()
{
    return ConsoleApp.Run("cmd", "/c ver").Output.Trim();
}

带有实时反馈的示例:

// Run ping.exe asynchronously and return roundtrip times back to the caller in a callback
public static void PingUrl(string url, Action<string> replyHandler)
{
    var regex = new Regex("(time=|Average = )(?<time>.*?ms)", RegexOptions.Compiled);
    var app = new ConsoleApp("ping", url);
    app.ConsoleOutput += (o, args) =>
    {
        var match = regex.Match(args.Line);
        if (match.Success)
        {
            var roundtripTime = match.Groups["time"].Value;
            replyHandler(roundtripTime);
        }
    };
    app.Run();
}

答案 4 :(得分:2)

我在O2 Platform(开源项目)中添加了一些辅助方法,允许您通过控制台输出和输入轻松编写与其他进程的交互脚本(参见http://code.google.com/p/o2platform/source/browse/trunk/O2_Scripts/APIs/Windows/CmdExe/CmdExeAPI.cs

对您来说也很有用,可能是允许查看当前进程的控制台输出的API(在现有控件或弹出窗口中)。有关更多详细信息,请参阅此博客文章:http://o2platform.wordpress.com/2011/11/26/api_consoleout-cs-inprocess-capture-of-the-console-output/(此博客还包含有关如何使用新进程的控制台输出的详细信息)

答案 5 :(得分:2)

添加了process.StartInfo.**CreateNoWindow** = true;timeout

private static void CaptureConsoleAppOutput(string exeName, string arguments, int timeoutMilliseconds, out int exitCode, out string output)
{
    using (Process process = new Process())
    {
        process.StartInfo.FileName = exeName;
        process.StartInfo.Arguments = arguments;
        process.StartInfo.UseShellExecute = false;
        process.StartInfo.RedirectStandardOutput = true;
        process.StartInfo.CreateNoWindow = true;
        process.Start();

        output = process.StandardOutput.ReadToEnd();

        bool exited = process.WaitForExit(timeoutMilliseconds);
        if (exited)
        {
            exitCode = process.ExitCode;
        }
        else
        {
            exitCode = -1;
        }
    }
}

答案 6 :(得分:1)

来自 PythonTR - Python Programcıları Derneği, e-kitap, örnek

Process p = new Process();   // Create new object
p.StartInfo.UseShellExecute = false;  // Do not use shell
p.StartInfo.RedirectStandardOutput = true;   // Redirect output
p.StartInfo.FileName = "c:\\python26\\python.exe";   // Path of our Python compiler
p.StartInfo.Arguments = "c:\\python26\\Hello_C_Python.py";   // Path of the .py to be executed

答案 7 :(得分:0)

我制作了一个响应式版本,可以接受stdOut和StdErr的回调。
onStdOutonStdErr被异步调用,
数据到达后(在流程退出之前)。

public static Int32 RunProcess(String path,
                               String args,
                       Action<String> onStdOut = null,
                       Action<String> onStdErr = null)
    {
        var readStdOut = onStdOut != null;
        var readStdErr = onStdErr != null;

        var process = new Process
        {
            StartInfo =
            {
                FileName = path,
                Arguments = args,
                CreateNoWindow = true,
                UseShellExecute = false,
                RedirectStandardOutput = readStdOut,
                RedirectStandardError = readStdErr,
            }
        };

        process.Start();

        if (readStdOut) Task.Run(() => ReadStream(process.StandardOutput, onStdOut));
        if (readStdErr) Task.Run(() => ReadStream(process.StandardError, onStdErr));

        process.WaitForExit();

        return process.ExitCode;
    }

    private static void ReadStream(TextReader textReader, Action<String> callback)
    {
        while (true)
        {
            var line = textReader.ReadLine();
            if (line == null)
                break;

            callback(line);
        }
    }


用法示例

以下内容将与executable一起运行args并打印

  • 白色stdOut
  • 红色的stdErr

到控制台。

RunProcess(
    executable,
    args,
    s => { Console.ForegroundColor = ConsoleColor.White; Console.WriteLine(s); },
    s => { Console.ForegroundColor = ConsoleColor.Red;   Console.WriteLine(s); } 
);