Question

我想通过Comp。

在各种html表组中显示以下数据库

TeamA         TeamB             Comp
Kenya     Namibia       Africa   World Cup - Qual
Zimbabwe      Mozambique       Africa World Cup - Qual
Coventry City Colchester Utd   England - League One 
Bray Wanderers UCD League Of   Ireland - Premier Division
Dundalk    Drogheda United  League Of Ireland - Premier Division

示例表1

Comp: Africa World Cup - Qual
Kenya     Namibia
Zimbabwe  Mozambique

示例表2

England - League One
Coventry City Colchester Utd

等

我试过

SELECT GROUP_CONCAT(Comp) as Comp 
  FROM database 
 Group By Comp`

但没有运气。

Answer 1

你在找这个吗？

SELECT comp,
       GROUP_CONCAT(CONCAT(TeamA, '|', TeamB)) details
  FROM table1
 GROUP BY comp

输出：

+--------------------------------------+--------------------------------------------+
| comp                                 | details                                    |
+--------------------------------------+--------------------------------------------+
| Africa World Cup - Qual              | Kenya|Namibia,Zimbabwe|Mozambique          |
| England - League One                 | Coventry City|Colchester Utd               |
| League Of Ireland - Premier Division | Bray Wanderers|UCD,Dundalk|Drogheda United |
+--------------------------------------+--------------------------------------------+

这是 SQLFiddle 演示

如果需要，您可以分别从逗号CONCAT()和管道GROUP_CONCAT()更改,和|中的分隔符。迭代结果集时，您可以轻松explode()详细说明值。

使用PDO的简化php部分可能看起来像这样

$db = new PDO('mysql:host=localhost;dbname=test', 'user', 'userpwd');
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$db->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);


$sql = "SELECT comp,
               GROUP_CONCAT(CONCAT(TeamA, '|', TeamB)) details
               FROM table1
         GROUP BY comp";

$query = $db->prepare($sql);
$query->execute();
$rows = $query->fetchall(PDO::FETCH_ASSOC);

$query = null;
$db = null;

foreach($rows as $row) {
    echo $row['comp'] . '</br>';
    $details = explode(',', $row['details']);
    foreach($details as $detail) {
        list($teama, $teamb) = explode('|', $detail);
        echo $teama . ' - ' .$teamb . '</br>';
    }
    echo '</br>';
}

输出：

Africa World Cup - Qual
Kenya - Namibia
Zimbabwe - Mozambique

England - League One
Coventry City - Colchester Utd

League Of Ireland - Premier Division
Bray Wanderers - UCD
Dundalk - Drogheda United

Answer 2

我认为你有数据库设计问题。我是否理解您的输出是在某场比赛中展示游戏？所以A队在C队比赛中对阵B队？

我认为你应该创建超过2个表。

表A：包含所有团队。
表B包含所有比赛（因为可能是一个团队可以参加一个以上的比赛）。
表C加入参赛队伍。
表D在某场比赛中举办比赛。

在表D中，我们仅链接表C中的记录。原因是为了防止团队参加未参与的比赛。

所以：

Table A (Teams) contains columns (idTeam INT, Teamname VARCHAR 50)
Table B (Competitions) contains columns (idComp INT, Competitionname VARCHAR 50)
Table C (TeamCompetitions) contains columns (idTeam INT, idComp INT)
Table D (Games) contains columns (idTeamCompA INT, idTeamCompB INT, idComp INT)

然后查询就不那么难了：

SELECT 
  TeamA.Teamname as teamA,
  TeamB.Teamname as teamB,
  comp.Competitionname as competition
FROM 
  Games 
     JOIN TeamCompetitions AS compTeamA ON compTeamA.idTeamCompetition = Games.idTeamCompA
     JOIN Teams            AS TeamA     ON compTeamA.idTeam = TeamA.idTeam
     JOIN TeamCompetitions AS compTeamB ON compTeamB.idTeamCompetition = Games.idTeamCompB
     JOIN Teams            AS TeamB     ON compTeamB.idTeam = TeamB.idTeam
     JOIN Competitions AS comp ON compTeamA.idCompetition = comp.idCompetition

一个例子：队

1   Zimbabwe
2   Kenya
3   AJAX
4   Chelsea
5   Feyenoord
6   PEC Zwolle

竞赛

1   World Championship 2014
2   Dutch Premier League

TeamCompetitions

游戏

查询输出：

teamA   teamB   competition
Zimbabwe    Zimbabwe    World Championship 2014
Zimbabwe    Kenya   World Championship 2014
Feyenoord   AJAX    Dutch Premier League
Feyenoord   PEC Zwolle  Dutch Premier League

希望这有帮助！

MYSQL和PHP组的结果由

2 个答案: