Question

我们正在制作一款基于文字的游戏（MUD），并且遇到了这个障碍。

代码：

class RoomMove():

    def __init__(self):
        self.room = 1
        self.name = 'Lorinth'
        self.moveRooms()
        self.updateRoom()

[额外代码无所谓]

def updateRoom(self):
        global c
        room = str(self.room)
        room = (room)
        print room
        while room > 0:
            c.execute("""SELECT * FROM RoomPlayers where ID=?""", room)
            spaceCheck = c.fetchone()
            print spaceCheck
            counter = 1
            if spaceCheck[counter] not in ('', None):
                counter += 1
            else:
                room = self.room
                name = self.name
                c.execute("""UPDATE RoomPlayers SET '1'=? WHERE ID=?""", (name, room))
        conn.commit()

它会抛出这个错误：

     c.execute("""SELECT * FROM RoomPlayers where ID=?""", room)
ValueError: parameters are of unsupported type

编辑：我已经尝试了（房间）..但错误没有区别。

有什么想法吗？

谢谢！

Answer 1

您可以阅读documentation：

fetchone（）

获取查询结果集的下一行，返回单个序列，或者在没有更多数据可用时获取“无”。

如果没有更多数据，c.fetchone（）会为spaceCheck变量分配None，因此当您尝试访问spaceCheck [counter]时会出现TypeError。

尝试类似的东西：

        if spaceCheck is not None:
            counter += 1

<强>更新

你应该替换

room = (room)

使用：

room = (room, )

另一次更新

假设您创建如下表格：

sqlite> CREATE TABLE RoomPlayers (ID numeric, player_name VARCHAR);

您的代码可能与此类似：

class RoomMove():

    def __init__(self, room, name):
        self.room = room
        self.name = name
        self.con = None
        self.db_path = "./foo.sqlite"

    def updateRoom(self):
        try:
            # Globals are evil. Don't use them 
            self.con = sqlite3.connect(self.db_path)
            c = con.cursor()
            # comparing tuple or string to number dosen't make sense. Compare original number
            # You should check if room is valid inside constructor
            #  while room > 0 would probably lead to indefinite loop
            if rooom > 0:
                #You don't have to cast room number to string
                c.execute("""SELECT id FROM RoomPlayers where ID=?""", (self.room, ))
                spaceCheck = c.fetchone()

                # Your counter takes only two values so you can do it like that
                counter = 2 if spaceCheck is not None else 1

                if counter == 1:
                    # Don't name columns '1' - it is really bad idea
                    # Like above - coneverting room and name to string is pointlees
                    c.execute("""UPDATE RoomPlayers SET 'player_name'=? WHERE ID=?""", (self.name, self.room))
                    self.con.commit()

        finally:
            # No matter what happens close connection
            if self.con is not None:
                self.con.close()

Answer 2

解决上述问题的原因是什么：

sqlite3不读取整数，只读取字符串。（实际上并非如此）

所以我将整数作为else循环中的字符串读取。

这里：

else:
        room = self.room
        name = self.name
        c.execute("""UPDATE RoomPlayers SET '1'=? WHERE ID=?""", (name, room))

房间正在作为整数传递给c.execute，解决方案？

else:
    room = str(self.room)
....

永远看到了！

Python sqlite3 NoneType错误

2 个答案: