使用从EditText获得的整数的Math

时间:2013-09-07 20:43:34

标签: android string int android-edittext

我不知道我做错了什么,但我有一个名为input的edittext,用户在那里写一个数字,然后你按一个按钮:

input = (EditText) findViewById(R.id.input);

    XX= (Button) findViewById(R.id.XX);
    XX.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View arg0) {

            if(XX.equals("XX"))
            {


                String aa= String.valueOf(input) ;
                float operation= ((float) ( 0.029 * 2.2 *aa ) );
                String cadena= String.valueOf(operation) ;

// set text to cadena (result of the operation)
                predic = (TextView) findViewById(R.id.predic);
                predic.setText(cadena);

            }

问题是我无法执行此操作

float operation =((float)(0.029 * 2.2 * aa));

因为它强调“aa”并说

“运算符'*'不能应用于'double','java.lang.String'”

我认为他认为aa是一个字符串,我怎么能把它作为一个Int来读?

LOGCAT1

09-07 23:18:07.915  10148-10148/com.example.XXXE/AndroidRuntime﹕ FATAL EXCEPTION: main
        java.lang.NumberFormatException: unable to parse 'android.widget.EditText@405a8b98' as integer
        at java.lang.Integer.parse(Integer.java:383)
        at java.lang.Integer.parseInt(Integer.java:372)
        at java.lang.Integer.parseInt(Integer.java:332)

    ***at com.example.XXX.XXX$5.onClick(XXX.java:542)***  CRASHES


    at android.view.View.performClick(View.java:2506)
    at android.view.View$PerformClick.run(View.java:9112)
    at android.os.Handler.handleCallback(Handler.java:587)
    at android.os.Handler.dispatchMessage(Handler.java:92)
    at android.os.Looper.loop(Looper.java:130)
    at android.app.ActivityThread.main(ActivityThread.java:3835)
    at java.lang.reflect.Method.invokeNative(Native Method)
    at java.lang.reflect.Method.invoke(Method.java:507)
    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:864)
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:622)
    at dalvik.system.NativeStart.main(Native Method)
09-07 23:18:07.965   3698-17447/system_process W/ActivityManager﹕ 
    Force finishing    activity com.example.XXXX/.XXXX

1 个答案:

答案 0 :(得分:1)

您需要更改:

 String aa= String.valueOf(input) ;

Int aa = Integer.parseInt(input.getText().toString());

只要您确定用户只会输入整数