java.lang.numberformatexception:无效的double:“”

时间:2013-09-07 10:41:26

标签: java android

收到无效Double的错误 java.lang.numberformatexception无效的双倍:“” 这是什么原因

活动1

package com.example.solarcalculator;

        import android.os.Bundle;
        import android.widget.Button;
        import android.annotation.SuppressLint;
        import android.app.Activity;
        import android.view.Menu;
        import android.view.View;
        import android.view.View.OnClickListener;
        import android.widget.EditText;
        import android.app.AlertDialog;
        import android.content.Intent;

        @SuppressLint("UseValueOf")
        public class MainActivity extends Activity {
            private EditText input1;
            private EditText input2;
            private EditText input3;
            private EditText input4;
            private EditText input5;
            private MainActivity mContext;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        mContext = this;
        setContentView(R.layout.activity_main);

        input5 = (EditText) findViewById(R.id.input5);
        Button button1 = (Button) findViewById(R.id.button1);
        input4 = (EditText) findViewById(R.id.input4);
        input1 = (EditText) findViewById(R.id.input1);
        input2 = (EditText) findViewById(R.id.input2);
        input3 = (EditText) findViewById(R.id.input3);
        button1.setOnClickListener(new OnClickListener() {

            @SuppressWarnings("unused")
            private AlertDialog show;

            @SuppressLint("UseValueOf")
            @Override
            public void onClick(View arg0) {
                if (  (input4.getText().toString() == " ") 
                        || (input4.getText().length() ==0) ||
                                                (input5.getText().length() == 0)                         
                        || (input5.getText().toString() == " ")){
                show = new      AlertDialog.Builder(mContext).setTitle("Error")
                            .setMessage("Some inputs are empty")
                            .setPositiveButton("OK", null).show();
                }
    else if ((input1.getText().length() != 0) &&
        (input3.getText().length() ==0) && (input2.getText().length() ==    0)){
                     double w = new Double(input3.getText().toString());
                     double t = new Double(input4.getText().toString());
                     double x = new Double(input5.getText().toString());
                     float e = 7;
                     double num = 1000*x;
                     double den = w*t*e;
                     double payback = num/den;
                     double money = w*t*e/1000;
         Intent intent = new Intent(MainActivity.this, Power.class);
                     intent.putExtra("payback", payback);
                     intent.putExtra("money", money);
                     startActivity(intent);

                }
    else if ((input1.getText().length() == 0) &&   (input3.getText().length() != 0) &&
                                (input2.getText().length() != 0)){
                     double t = new    
                                     Double(input4.getText().toString());
                     double x = new Double(input5.getText().toString());
                     double v = new Double(input2.getText().toString());
                     double i = new Double(input3.getText().toString());
                     float e = 7;
                     double num = 1000*x;
                     double den = v*i*t*e;
                     double payback = num/den;
                     double money = v*i*t*e/1000;
             Intent intent = new Intent(MainActivity.this, Power.class);
                     intent.putExtra("payback", payback);
                     intent.putExtra("money", money);
                     startActivity(intent);

                }
                else {
                    double t = new Double(input4.getText().toString());
                     double x = new Double(input5.getText().toString());
                     double v = new Double(input2.getText().toString());
                     double i = new Double(input3.getText().toString());
                     float e = 7;
                     double num = 1000*x;
                     double den = v*i*t*e;
                     double payback = num/den;
                     double money = v*i*t*e/1000;
               Intent intent = new Intent(MainActivity.this, Power.class);
                     intent.putExtra("payback", payback);
                     intent.putExtra("money", money);
                     startActivity(intent);

                }
            }
        });

    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.main, menu);
        return true;
    }

       }

活性2

package com.example.solarcalculator;

    import android.annotation.SuppressLint;
    import android.app.Activity;
    import android.os.Bundle;
    import android.widget.TextView;
   @SuppressLint("NewApi")
     public class Power extends Activity {

private double money;
private double payback;

@SuppressLint("NewApi")
@Override
protected void onCreate(Bundle savedInstanceState) {
    // TODO Auto-generated method stub
    super.onCreate(savedInstanceState);
    setContentView(R.layout.power);
    payback = getIntent().getDoubleExtra("payback",0);
    money = getIntent().getDoubleExtra("money", 0);
    TextView pay = (TextView) findViewById(R.id.textView2);
    String payback1 = Double.toString(payback);
    pay.setText(payback1);
    TextView mon = (TextView) findViewById(R.id.textView4);
    String money1 = Double.toString(money);
    mon.setText(money1);

     }
    }

我收到java.lang.numberformatexception无效的双重:“”logcat中的错误 有人请帮忙

5 个答案:

答案 0 :(得分:22)

原因是,“”不是有效的双倍。您需要先测试String或捕获此类异常

double w;

try {
    w = new Double(input3.getText().toString());
} catch (NumberFormatException e) {
    w = 0; // your default value
}

答案 1 :(得分:5)

double的值取决于设备的语言。例如,对于法语设备,数字 0.179927 变为 0,179927 ,它将始终抛出{ {1}}因为逗号而将其解析为NumberFormatException

您需要将分隔符从double更改为comma。 您可以通过设置区域设置或使用point来更改分隔符。

如果您希望分组分隔符为点,则可以使用欧洲语言环境:

DecimalFormatSymbols

或者,您可以使用NumberFormat nf = NumberFormat.getNumberInstance(Locale.GERMAN); DecimalFormat df = (DecimalFormat)nf; 类更改DecimalFormatSymbols方法生成的格式化数字中出现的符号。这些符号包括小数分隔符,分组分隔符,减号和百分号等等:

format

答案 2 :(得分:3)

你应该这样做。把它放在try catch块中

   double w = new Double(input3.getText().toString());

答案 3 :(得分:0)

基本上,您需要测试要转换为双精度字符串是否为空

如果它是,则只需初始化它并添加一些值,然后再继续操作即可。

例如:

if(myString.isEmpty()){
myString = ""+0.0;
}
double answer = Double.parseDouble(myString);

答案 4 :(得分:0)

 double latitude;
            double longitude;
            try {
                latitude = Double.parseDouble(mApoAppointmentBeanList.get(position).getLatitude());
                longitude = Double.parseDouble(mApoAppointmentBeanList.get(position).getLongitude());

                String uri = String.format(Locale.ENGLISH, "http://maps.google.com/maps?q=loc:%f,%f", latitude, longitude);
                Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(uri));
                startActivity(intent);

            } catch (NumberFormatException e) {
                // your default value
                Toast.makeText(AppointmentsActivity.this, "Invalid location", Toast.LENGTH_LONG).show();
            }