Question

我有一个扩展BaseUser的自定义User类。

我被告知，为了利用用户锁定功能，我的用户类需要实现AdvancedUserInterface，但似乎我不能在User类上同时执行EXTENDS和IMPLEMENTS？

<?php
// src/BizTV/UserBundle/Entity/User.php

namespace BizTV\UserBundle\Entity;

use BizTV\UserBundle\Validator\Constraints as BizTVAssert;
use Symfony\Component\Security\Core\User\AdvancedUserInterface;

use FOS\UserBundle\Entity\User as BaseUser;
use Doctrine\ORM\Mapping as ORM;

use BizTV\BackendBundle\Entity\company as company;

/**
 * @ORM\Entity
 * @ORM\Table(name="fos_user")
 */
class User extends BaseUser implements AdvancedUserInterface
{

使用这种方法我没有收到任何错误消息，但我也没有使用这些函数来检查用户锁定，所以似乎没有任何反应。

如果我这样切换它们，

class User implements AdvancedUserInterface extends BaseUser

我收到以下错误消息：

Parse error: syntax error, unexpected T_EXTENDS, expecting '{' in /var/www/cloudsign/src/BizTV/UserBundle/Entity/User.php on line 18

Answer 1

好的，我解决了这个问题：

向用户实体添加我自己的函数以获取Lock状态（我没有定义的变量，它已经在我正在扩展的用户类中

//Below should be part of base user class but doesn't work so I implement it manually.

/**
 * Get lock status
 *
 * @return boolean 
 */
public function getLocked()
{
    return $this->locked;
}

在UserChecker中，我把它放在了：

public function checkPreAuth(UserInterface $user)
{

    //Test for companylock...
    if ( !$user->getCompany()->getActive() ) {
        throw new LockedException('The company of this user is locked.', $user);
    }    

    if ( $user->getLocked() ) {
        throw new LockedException('The admin of this company has locked this user.', $user);
    }

...

/**
 * {@inheritdoc}
 */
public function checkPostAuth(UserInterface $user)
{

    //Test for companylock...
    if ( !$user->getCompany()->getActive() ) {
        throw new LockedException('The company of this user is locked.', $user);
    }    

    if ( $user->getLocked() ) {
        throw new LockedException('The admin of this company has locked this user.', $user);
    }

symfony2如何在扩展BaseUser的User类上实现AdvancedUserInterface？

1 个答案: