Question

我只是想知道如何在下面提到的查询中添加count函数，其中我只需要显示那些p_id的计数应该等于1的记录

select Distinct p_id,i.img_path as ImagesName, 
(
  select p.project_details from [Project] p where p.p_id=i.p_id
) as ProjectName
from [p_Image] i

Answer 1

请尝试：

SELECT 
    * 
FROM(
    select 
        p_id, 
        i.img_path as ImagesName, 
        (
          select p.project_details from [Project] p where p.p_id=i.p_id
        ) as ProjectName,
        COUNT(*) OVER (PARTITION BY p_id) CNT
    from [p_Image] i
)x WHERE CNT=1

Answer 2

试试这个：

select p_id, i.img_path as ImagesName, p.project_details as ProjectName, count(*) as sum
from [p_Image] i
join [Project] p on (p.p_id=i.p_id)
group by p_id
having sum = 1;

Answer 3

您的查询相当于：

select p_id, i.img_path as ImagesName, p.project_details as ProjectName
from p_Image i left outer join
     project p
     on p.p_id=i.p_id;

以下是获得“独特”p_id的两种方法：

select p_id, min(i.img_path) as ImagesName, min(p.project_details) as ProjectName
from p_Image i left outer join
     project p
     on p.p_id = i.p_id
group by p_id
having count(*) = 1;

逻辑：当计数为1时，min() img_path和project_details只有一个值。 min()会返回该值。

以下使用带有窗口函数的子查询：

select p_id, ImagesName, ProjectName
from (select p_id, i.img_path as ImagesName, p.project_details as ProjectName,
             count(*) over (partition by p_id) as cnt
      from p_Image i left outer join
           project p
           on p.p_id=i.p_id
     ) pi
where cnt = 1;

如何在下面提到的查询中使用count函数？

3 个答案: