我正在开发一个集成jqGrid的自定义joomla 2.5组件。
我设置一个控制器任务来处理(更新mysql记录)从jqGrid postData发送的数据
var grid = jQuery(\"#list\");
grid.jqGrid({
onSelectRow: function(id){
$('#list').editRow(id, true);
},
url: '/index.php?option=com_nutraidev&view=products&format=raw',
datatype: 'json',
mtype: 'GET',
colNames: [...],
rowNum: 25,
rowList: [5, 10, 20, 50],
height: 'auto',
pager: '#pager',
loadonce: true,
sortname: 'ID',
viewrecords: true,
direction:'RTL',
autowidth: true,
sortorder: \"desc\",
caption: 'abc',
width: '70%',
editurl:'/index.php?option=com_nutraidev&view=products&task=Products.save&token=". JUtility::getToken() ."=1',
postData: {'code':\" \",....},
.....
这是发出请求的网址
/index.php?option=com_nutraidev&view=products&task=Products.save&token=". JUtility::getToken() ."=1&format=raw
我得到:
error 500
Invalid controller: name='products', format='raw'
使用实际令牌从浏览器中尝试了它 - 结果相同。
这是我的代码的重要部分:
com_nutraidev - 控制器 - products.php
require_once JPATH_COMPONENT.'/controller.php';
class NutraidevControllerProducts extends NutraidevController
{
public function &getModel($name = 'Products', $prefix = 'NutraidevModel')
{
$model = parent::getModel($name, $prefix, array('ignore_request' => true));
return $model;
}
public function save()
{
// Check for request forgeries.
JSession::checkToken() or jexit(JText::_('JINVALID_TOKEN'));
// Initialise variables.
$app = JFactory::getApplication();
$model = $this->getModel('Products', 'NutraidevModel');
$data = JRequest::get('get');
// Attempt to save the data.
$return = $model->updItem($data);
}
}
com_nutraidev - 楷模 - products.php
jimport('joomla.application.component.modellist');
class NutraidevModelProducts extends JModelList {
public function __construct($config = array()) {
parent::__construct($config);
}
public function updItem($data)
{
// set the variables from the passed data
$code = $data['code'];
$name = $data['name'];
// set the data into a query to update the record
$db = $this->getDbo();
$query = $db->getQuery(true);
$query->clear();
$query->update(' #__product ');
$query->set(' name = '.$db->Quote($name) );
$query->where(' code = ' . (int) $code );
$db->setQuery((string)$query);
if (!$db->query()) {
JError::raiseError(500, $db->getErrorMsg());
return false;
} else {
return true;
}
}
}
com_nutraidev - 意见 - 产品 - view.raw.php
jimport('joomla.application.component.view');
class NutraidevViewProducts extends JView
{
/ ** *显示视图 * / 公共函数显示($ tpl = null) { $ app = JFactory :: getApplication();
$document = JFactory::getDocument();
// Get data from the model
$items = $this->get('Items');
$this->state = $this->get('State');
$this->params = $app->getParams('com_nutraidev');
// Check for errors.
if (count($errors = $this->get('Errors'))) {;
throw new Exception(implode("\n", $errors));
}
// Assign data to the view
$response->page = 1;//JRequest::getVar('page');
$response->total = 1;//JRequest::getVar('total');
$response->records = count($items);
$i=0;
for ($i = 0; $i < count($items); ++$i) {
$response->rows[$i]['id'] = intval($items[$i]->code); //id
$response->rows[$i]['cell'] = array($items[$i]->code,
$items[$i]->name
);
}
echo json_encode($response);
jexit();
}
public function save($tpl = null)
{
echo "test";
jexit();
}
}
查看具有类似问题的其他问题,我仔细检查了我的
administrator/components/nutraidev/nutraidev.xml
并确保
<files folder="site">
<filename>controller.php</filename>
在那里。
我可能会遇到此错误的原因是什么?我也用view.json.php尝试了 并得到了相同的结果。感谢