结束到10年代

Question

我是Python的初学者。我希望将代码整理到每10个，例如。从33到30岁。

到目前为止，这是代码：

def roundoff(a, b):
    b = round(b)
    print str(a) + " you are around " + str(b) + " years old."

>>> roundoff("Bob", 33)
Bob you are around 33.0 years old.

---

我该如何解决？

Answer 1

定义自己的功能：

def my_round(x):
    return x - (x % 10) #or py2.x: (b/10)*10, py3.x: (b//10)*10
... 
>>> my_round(33)
30
>>> my_round(333)
330

使用字符串格式代替使用连接和str()转换：

>>> def roundoff(a, b):
...        b = b - (b % 10)
...        print "{} you are around {} years old.".format(a, b)
...     
>>> roundoff('bob', 33)
bob you are around 30 years old.
>>> roundoff('bob', 97)
bob you are around 90 years old.

Answer 2

您可以简单地执行以下操作：

def roundoff(name,age):
   age = age - age%10 #the % operator will get the rest of the division by 10 
                      #(so from 33 will get 3)
   print str(name) + " you are around " + str(age) + " years old."

希望有所帮助

Answer 3

你可以这样做：

def roundoff(name, age):
    print '%s, you are around %d years old.' % (name, (age /10) * 10)

当/运算符将int除以int时，它返回另一个int。因此，当您将33除以10时，结果将是3而不是3.3。在此之后，您只需将结果乘以10即可。