我注意到std :: vector和boost :: stable_vector之间存在很大的性能差异。下面是我构建并在向量和稳定向量中插入100,000个int的示例。
TEST.CPP:
#include <iostream>
#include <vector>
#include <boost/container/stable_vector.hpp>
#include <boost/timer/timer.hpp>
int main(int argc, char** argv) {
int size = 1e5;
boost::timer::cpu_timer timer;
timer.start();
std::vector<int> vec(size);
timer.stop();
std::cout << timer.format();
timer.start();
boost::container::stable_vector<int> svec(size);
timer.stop();
std::cout << timer.format();
}
编译:
g++ -O3 test.cpp -o test -lboost_system-mt -lboost_timer-mt
输出:
0.000209s wall, 0.000000s user + 0.000000s system = 0.000000s CPU (n/a%)
5.697013s wall, 5.690000s user + 0.000000s system = 5.690000s CPU (99.9%)
造成这种巨大差异的原因是什么?我的理解是两种类型都应具有相似的插入性能。
更新: 提升版:1.54
dev/stable_vector_test: g++ --version
i686-apple-darwin11-llvm-g++-4.2 (GCC) 4.2.1 (Based on Apple Inc. build 5658) (LLVM build 2336.11.00)
Copyright (C) 2007 Free Software Foundation, Inc.
This is free software; see the source for copying conditions. There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
我在代码中添加了std :: list,并尝试在-O3之外传递-DNDEBUG。
dev/stable_vector_test: make
g++ -g test.cpp -o test -lboost_system-mt -lboost_timer-mt
dev/stable_vector_test: ./test
size: 10000
vector: 0.000047s wall, 0.000000s user + 0.000000s system = 0.000000s CPU (n/a%)
list: 0.001168s wall, 0.000000s user + 0.000000s system = 0.000000s CPU (n/a%)
stable_vector: 0.963679s wall, 0.960000s user + 0.000000s system = 0.960000s CPU (99.6%)
dev/stable_vector_test: make opt
g++ -O3 -DNDEBUG test.cpp -o test -lboost_system-mt -lboost_timer-mt
dev/stable_vector_test: ./test
size: 10000
vector: 0.000038s wall, 0.000000s user + 0.000000s system = 0.000000s CPU (n/a%)
list: 0.000659s wall, 0.000000s user + 0.000000s system = 0.000000s CPU (n/a%)
stable_vector: 0.000752s wall, 0.000000s user + 0.000000s system = 0.000000s CPU (n/a%)
因此,使用-O3和-DNDEBUG,我可以获得与std :: list
相当的性能答案 0 :(得分:5)
由于stable_vector
不使用连续存储,因此分配其初始内存比std::vector
花费更长的时间似乎是合理的。
如a background post on stable_vector所述,stable_vector
的一种可能实现涉及为向量的每个元素分配一个单独的节点。当然,the source code for the stable_vector
构造函数显示它调用resize
,它使用一对迭代器调用insert
,insert
执行N节点分配:
// (initialization...)
while(first != last){
const node_ptr p = this->priv_get_from_pool();
BOOST_ASSERT(!!p);
//Put it in the index so rollback can return it
//in pool if construct_in_place throws
*it_past_newly_constructed = p;
//Constructs and fixes up pointers This can throw
this->priv_build_node_from_it(p, it_past_newly_constructed, first);
++first;
++it_past_newly_constructed;
}
所以它正在执行类似于std::list
的操作,您的数据支持这些内容。