我有一个带有Service
集合的域tags
,如下所示:
@Entity
public class Service extends AbstractEntity<Long> {
private static final long serialVersionUID = 9116959642944725990L;
@ElementCollection(fetch = FetchType.EAGER, targetClass = java.lang.String.class)
@CollectionTable(name = "service_tags", joinColumns = @JoinColumn(name = "s_id"))
@Column(name = "tag")
private Set<String> tags;
}
我想选择Service
with
KEY
Service.tags
hql
。
Service
加入Service.tags
至select s from Service s INNER JOIN s.tags t where s.status=0 and (s.serviceType=9 or t.tag in ('College'))
如下:
Caused by: java.lang.IllegalArgumentException: org.hibernate.QueryException: cannot dereference scalar collection element: tag [select s from com.zazzercode.domain.Service s INNER JOIN s.tags t where s.status=0 and (s.serviceType=9 or t.tag in ('College')) ]
但是,上面的hql会返回以下异常:
select s from Service s INNER JOIN s.tags t where s.status=0
"select s from Service s where s.status=0 and s.priviligedUser.priviligedUserType IN (2,4) and (s.serviceType=9 or (KEY(s.tags)='tag' and (VALUE(s.tags)='College'))"
虽然有效。
查看JPQL querying a collection of non-entites,我尝试过以下
Caused by: org.hibernate.hql.ast.QuerySyntaxException: unexpected token: null near line 1, column 188 [select s from com.esewa.server.entity.Service s where s.status=0 and (s.serviceType=9 or (KEY(s.tags)='tag' and (VALUE(s.tags)='College'))]
遇到以下异常:
{{1}}
几个月前我已经完成了相同的事情using criteria api。
答案 0 :(得分:3)
"select s from Service s where s.status=0 and (s.serviceType=9 or 'College' in elements(s.tags))"
答案 1 :(得分:1)
感谢JPQL querying a collection of non-entites
"select s from Service s INNER JOIN s.tags t where s.status=0 and and (s.serviceType=9 or VALUE(s.tags) in ('College')) "