对于我的项目,我试图在客户端中截取屏幕截图并通过套接字将其发送到服务器。我用一个循环来截取,直到手动停止。但是虽然拍摄截图很好,但是在发送一些图像后只变成主图像的一半而一些图像已经满了
的客户端:
我正在截取这个截图
bmpScreenshot = new Bitmap(Screen.PrimaryScreen.Bounds.Width, Screen.PrimaryScreen.Bounds.Height, PixelFormat.Format32bppArgb);
gfxScreenshot = Graphics.FromImage(bmpScreenshot);
gfxScreenshot.CopyFromScreen(Screen.PrimaryScreen.Bounds.X, Screen.PrimaryScreen.Bounds.Y, 0, 0, Screen.PrimaryScreen.Bounds.Size, CopyPixelOperation.SourceCopy);
bmpScreenshot.Save(path + i + ".png");
ClientService.SendFile(path + i + ".png");
i++;
,SendFile方法是
public static void SendFile(string fileName)
{
try
{
IPAddress[] ipAddress = Dns.GetHostAddresses("localhost");
IPEndPoint ipEnd = new IPEndPoint(ipAddress[0], 5656);
Socket clientSock = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);
string filePath = "";
fileName = fileName.Replace("\\", "/");
while (fileName.IndexOf("/") > -1)
{
filePath += fileName.Substring(0, fileName.IndexOf("/") + 1);
fileName = fileName.Substring(fileName.IndexOf("/") + 1);
}
byte[] fileNameByte = Encoding.ASCII.GetBytes(fileName);
if (fileNameByte.Length > 600 * 1024)
{
showMsg = "File size is more than 600kb, please try with small file.";
return;
}
byte[] fileData = File.ReadAllBytes(filePath + fileName);
byte[] clientData = new byte[4 + fileNameByte.Length + fileData.Length];
byte[] fileNameLen = BitConverter.GetBytes(fileNameByte.Length);
fileNameLen.CopyTo(clientData, 0);
fileNameByte.CopyTo(clientData, 4);
fileData.CopyTo(clientData, 4 + fileNameByte.Length);
clientSock.Connect(ipEnd);
clientSock.Send(clientData);
clientSock.Close();
}
catch (Exception ex)
{
if (ex.Message == "No connection could be made because the target machine actively refused it")
showMsg = "File Sending fail. Because server is not running.";
else
showMsg = "File Sending fail." + ex.Message;
}
}
服务器
IPEndPoint ipEnd;
Socket sock;
public ServerService()
{
ipEnd = new IPEndPoint(IPAddress.Any, 5656);
sock = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);
sock.Bind(ipEnd);
}
public static string receivedPath;
internal void StartServer()
{
try
{
sock.Listen(100);
Socket clientSock = sock.Accept();
byte[] clientData = new byte[1024 * 5000];
int receivedBytesLen = clientSock.Receive(clientData);
int fileNameLen = BitConverter.ToInt32(clientData, 0);
string fileName = Encoding.ASCII.GetString(clientData, 4, fileNameLen);
BinaryWriter bWrite = new BinaryWriter(File.Open(receivedPath + "/" + fileName, FileMode.Append)); ;
bWrite.Write(clientData, 4 + fileNameLen, receivedBytesLen - 4 - fileNameLen);
bWrite.Close();
clientSock.Close();
}
catch (Exception ex)
{
ShowMsg = "Something is wrong." + ex.Message;
}
}
我该如何解决这个问题?
答案 0 :(得分:2)
Receive
仅保证(其中之一):
仅拨打Receive
一次是不够的。您需要在循环中将其称为,直到:
在你的情况下,我建议你想:
n
n
个字节以读取名称Receive
的非阳性结果)另外:您可能希望使用基于Stream
的API来进行文件访问(包括读取和写入),而不是File.ReadAllBytes
或BinaryWriter
。
读取完全 n
字节的情况类似于:
public void ReceiveExactly(Socket socket, byte[] buffer, int offset, int count)
{
int read;
while(count > 0 && (read = socket.Receive(buffer, offset, count,
SocketFlags.None)) > 0)
{
offset += read;
count -= read;
}
if(count != 0) throw new EndOfStreamException();
}