Question

结果字符串包含输入字符串：1 2 3 a b c

预期的操作：

1 a
2 b
3 c

我尝试了什么：

resultKV=result.Split('\t');
foreach (string KV in resultKV)
{
    Console.WriteLine(KV);                    
}

Answer 1

var parts  = "1 2 3 a b c".Split();
var dict = parts.Select((s, inx) => new { s = s, inx = inx })
                .GroupBy(x => x.inx % (parts.Length / 2))
                .ToDictionary(x => x.First().s, x => x.Last().s);

使用副作用，可以缩短

var parts  = "1 2 3 a b c".Split();
int inx = 0;

var dict = parts.GroupBy(x => inx++ % (parts.Length / 2))
                .ToDictionary(x => x.First(), x => x.Last());

Answer 2

string input = "1 2 3 a b c";
var parts = input.Split(' ');
if (parts.Length % 2 == 0)
{
    var d = new Dictionary<string, string>();
    var halfLength = parts.Length / 2;
    for (int i = 0; i < halfLength; i++)
    {
        d[parts[i]] = parts[halfLength + i];
    }

    // at this stage the dictionary will contain the desired result
}
else
{
    Console.WriteLine("Must have a pair number to build the dictionary");
}

Answer 3

拆分会导致多个项目吗？换句话说：它是正确的逃脱序列吗？如果是这样，也许你可以做任何事情：

int l = resultKV.lenght/2;

if(l % 2 == 0)

for(int i = 0; i < l; i++){

Console.WriteLine(resultKV[i]); Console.WriteLine(resultKV[i+l]);

} （未经测试）

c＃中字符串到字典的转换

3 个答案: