Question

我被要求处理别人用cakePHP创建的应用程序。我是cakePHP的新手。该应用程序显示以下错误

Notice(8):

    if(isset($client[0]) && $client[0]['contacts']['type_of']==3 && $var=='clients_with_contacts' && $this->Paginator->current()==1){
                                echo '<td style="background:lightblue">'.$client[0]['Client'][$field].'</td>';

include - APP/View/Clients/index.ctp, line 90
View::_evaluate() - CORE/Cake/View/View.php, line 947
View::_render() - CORE/Cake/View/View.php, line 909
View::render() - CORE/Cake/View/View.php, line 471
Controller::render() - CORE/Cake/Controller/Controller.php, line 948
Dispatcher::_invoke() - CORE/Cake/Routing/Dispatcher.php, line 194
Dispatcher::dispatch() - CORE/Cake/Routing/Dispatcher.php, line 162
[main] - APP/webroot/index.php, line 112

有很多代码。如果你能想到任何事情，请告诉我。

Answer 1

一种可能的解决方案是在条件中检查变量'$ var'和'$ client [0] ['contacts'] ['type_of']'，如下所示：

if(isset($client[0]['contacts']['type_of']) && $client[0]['contacts']['type_of']==3 && isset($var) && $var=='clients_with_contacts' && $this->Paginator->current()==1){

echo '<td style="background:lightblue">'.$client[0]['Client'][$field].'</td>';

}

Answer 2

在ClientsController中，检查$ client，并通过以下方式正确传输$ var：

$this->set ('client', $variable1);
$this->set ('var', $variable2);

或

$this->set (array ('client' => $variable1, 'var' => $variable2));

如果是，请检查$client数组的所有字段是否也存在。同样在您的代码中，if语句也错过了}。

未定义的索引：URL [APP / View / Clients / index.ctp，第90行]

2 个答案: