Question

我正在创建一个读取文件的程序，并打印出它包含的每个单独字母的数量（如果有的话）。如果文件中包含“hello world”，我希望它打印1h，1e，3l，2o，1w，1r，1l等。这不是一个工作项目或任何东西，我这样做是出于兴趣。我似乎无法找到一个示例代码来执行此操作，这就是为什么我以为我会问这里:)想知道我的代码应该是什么样的。

a1 = 0
b1 = 0
c1 = 0
d1 = 0
e1 = 0
f1 = 0
g1 = 0
h1 = 0
i1 = 0
j1 = 0
k1 = 0
l1 = 0
m1 = 0
n1 = 0
o1 = 0
p1 = 0
q1 = 0
r1 = 0
s1 = 0
t1 = 0
u1 = 0
v1 = 0
w1 = 0
x1 = 0
y1 = 0
z1 = 0
with open("song.txt") as f:
    for line in f:
        if line == "a" or line == "A":
            a1 = a1 + 1
        if line == "b" or line == "B":
            b1 - b1 + 1
        if line == "c" or line == "C":
            c1 = c1 + 1
        if line == "d" or line == "D":
            d1 = d + 1
        if line == "e" or line == "e":
            e1 = e1 + 1
        if line == "f" or line == "F":
            f1 = f1 + 1
        if line == "g" or line == "G":
            g1 = g1 + 1
        if line == "h" or line == "H":
            h1 = h1 + 1
        if line == "i" or line == "I":
            i1 = i1 + 1
        if line == "j" or line == "J":
            j1 = j1 + 1
        if line == "k" or line == "K":
            k1 = k1 + 1
        if line == "l" or line == "L":
            l1 = l1 + 1
        if line == "m" or line == "M":
            m1 = m1 + 1
        if line == "n" or line == "N":
            n1 = n1 + 1
        if line == "o" or line == "O":
            o1 = o1 + 1
        if line == "P" or line == "p":
            p1 = p1 + 1
        if line == "q" or line == "Q":
            q1 = q1 + 1
        if line == "r" or line == "R":
            r1 = r1 + 1
        if line == "S" or line == "s":
            s1 = s1 + 1
        if line == "T" or line == "t":
            t1 = t1 + 1
        if line == "u" or line == "U":
            u1 = u1 + 1
        if line == "v" or line == "V":
            v1 = v1 + 1
        if line == "w" or line == "W":
            w1 = w1 + 1
        if line == "x" or line == "X":
            x1 = x1 + 1
        if line == "y" or line == "Y":
            y1 = y1 + 1
        if line == "z" or line == "Z":
            z1 = z1 + 1fwef
print(a1,b1,c1,d1,e1,f1,g1,h1,i1,j1,k1,l1,m1,n1,o1,p1,q1,r1,s1,t1,u1,v1,w1,x1,y1,z1)

Answer 1

这将：

将整个文件作为小写字符阅读，
提取所有作为列表找到的字符并按字母数字排序，

打印每个字符及其出现次数。

from collections import Counter
with open('song.txt') as f:
count = Counter(f.read().lower())
keys = list(count)
keys.sort()
for x in keys:
    print '{0}: {1} times'.format(x, count[x])

Answer 2

试试这个...这将分别计算大写和小写字母。

import string
fp=open('song.txt','r')
file_list=fp.readlines()
freqs = {}
for line in file_list:
    for char in line:
        line=filter(lambda x:x in strings.letters, line.lower())
        if char in freqs:
            freqs[char] += 1
        else:
            freqs[char] = 1
for item in freqs:
    print item, freqs[item]

或者只在小写字母的for循环后将行转换为小写。

Answer 3

你的方法可能会有一些修改，但它真的很难处理（更不用说容易出错了）。你可能想要做的是使用一个名为 dictionary 的Python数据结构，它将一个键（一个字母）与一个值（count）相关联。所以你可以这样做：

letters = {}
with open("song.txt") as f:
    for c in f.read():
        c = c.lower()
        if "a" <= c <= "z":
            if c not in letters:
                letters[c] = 0
            letters[c] += 1
for c, n in sorted(letters.items()):
    print("{0}{1}".format(c, n))

请注意f.read()将整个文件读入内存，然后for c in f.read()循环分别遍历每个字符。如果您只计算字符数，则无需将文件分成几行。

这是Python中的常见模式，你会发现有一个名为Counter的标准库实用程序可以完成大部分工作（此处的另一个答案显示了如何使用它）。

程序不会在文件中正确打印出字母数

3 个答案: