我想检索有人以字符串形式输入的内容，我假设它是我需要的子字符串，但我不确定如何。
当用户输入混合了单词和数字的字符串时，所有字符串都用一个空格分隔： 嘿110说“我不是很擅长Java”但是“我能钓得很好”
然后我希望能够采用“我不是很擅长Java”和“我能钓得很好”并打印出引号内的内容，以便字符串中可以有多个引号。 现在我有if（userInput =='“'）然后我用子串做一些事情，但我不确定是什么。
我不能使用分割，修剪，标记器，正则表达式或任何会让这个变得非常简单的事情。
这一切都在这个方法中我尝试识别字符串中的某些东西是单词，数字还是引用：
public void set(String userInput)// method set returns void
{
num=0;// reset each variable so new input can be passed
String empty="";
String wordBuilder="";
userInput+=" ";
for(int index=0; index<userInput.length(); index++)// goes through each character in string
{
if(Character.isDigit(userInput.charAt(index)))// checks if character in the string is a digit
{
empty+=userInput.charAt(index);
}
else
{
if (Character.isLetter(userInput.charAt(index)))
{
wordBuilder+=userInput.charAt(index);
}
else
{
if(userInput.charAt(index)=='"')
{
String quote=(userInput.substring(index,);
}
}
//if it is then parse that character into an integer and assign it to num
num=Integer.parseInt(empty);
word=wordBuilder;
empty="";
wordBuilder="";
}
}
}
}
谢谢！
答案 0 :(得分：2)
尝试下一个：
public static void main(String[] args) {
String input = "\"123\" hey 110 say \"I am not very good at Java\" but \" I can fish pretty well\"";
int indexQuote = -1;
boolean number = true;
String data = "";
for (int i = 0; i < input.length(); i++) {
char ch = input.charAt(i);
if (Character.isWhitespace(ch)) {
if (data.length() > 0 && indexQuote == -1) {
if (number) {
System.out.println("It's a number: " + data);
} else {
System.out.println("It's a word: " + data);
}
// reset vars
number = true;
data = "";
} else if (indexQuote != -1) {
data += ch;
}
} else if (ch == '"') {
if (indexQuote == -1) {
number = false;
indexQuote = i;
} else {
System.out.println("It's a quote: " + data);
// reset vars
number = true;
data = "";
indexQuote = -1;
}
} else {
if (!Character.isDigit(ch)) {
number = false;
}
data += ch;
if (data.length() > 0 && i == input.length() - 1) {
if (number) {
System.out.println("It's a number: " + data);
} else {
System.out.println("It's a word: " + data);
}
}
}
}
}
输出：
It's a word: hey
It's a number: 110
It's a word: say
It's a quote: I am not very good at Java
It's a word: but
It's a quote: I can fish pretty well
答案 1 :(得分：0)
迭代字符串并使用临时int变量来存储引用的字符串。当你看到它结束时，你可以提取那个子串并用它做你想做的事。
答案 2 :(得分：0)
答案 3 :(得分：0)
public class MyTestSecond {
public static void main(String...args){
String a = "hey 110 say \"I am not very good at Java\"";
// Method 1
if(a.contains("\""))
System.out.println(a.substring(a.indexOf("\""),a.lastIndexOf("\"")+1));
//Method 2
String[] array = a.split(" ");
for(int i=0;i<array.length;i++){
if(array[i].startsWith("\""))
System.out.println(a.substring(a.indexOf("\""),a.lastIndexOf("\"")+1));
}
}
}
答案 4 :(得分：0)
我不确定这是否正是您所寻找的，但它会逐步删除所引用的部分......
String quote = "I say: \"I have something to say, \"It's better to burn out then fade away\"\" outloud...";
if (quote.contains("\"")) {
while (quote.contains("\"")) {
int startIndex = quote.indexOf("\"");
int endIndex = quote.lastIndexOf("\"");
quote = quote.substring(startIndex + 1, endIndex);
System.out.println(quote);
}
}
哪些输出......
I have something to say, "It's better to burn out then fade away"
It's better to burn out then fade away
<强>更新
我不知道这是不是在作弊......
String quote = "I say: \"I have something to say, \"It's better to burn out then fade away\"\" outloud...\"Just in case you don't believe me\"";
String[] split = quote.split("\"");
for (String value : split) {
System.out.println(value);
}
哪些输出......
I say:
I have something to say,
It's better to burn out then fade away
outloud...
Just in case you don't believe me
<强>更新
好的，假的String#split
StringBuilder sb = new StringBuilder(quote.length());
for (int index = 0; index < quote.length(); index++) {
if (quote.charAt(index) == '"') {
System.out.println(sb);
sb.delete(0, sb.length());
} else {
sb.append(quote.charAt(index));
}
}
<强>更新
好的，这基本上是假的split，带有选项......
String quote = "blah blah 123 \"hello\" 234 \"world\"";
boolean quoteOpen = false;
StringBuilder sb = new StringBuilder(quote.length());
for (int index = 0; index < quote.length(); index++) {
if (quote.charAt(index) == '"') {
if (quoteOpen) {
System.out.println("Quote: [" + sb.toString() + "]");
quoteOpen = false;
sb.delete(0, sb.length());
} else {
System.out.println("Text: [" + sb.toString() + "]");
sb.delete(0, sb.length());
quoteOpen = true;
}
} else {
sb.append(quote.charAt(index));
}
}
if (sb.length() > 0) {
if (quoteOpen) {
System.out.println("Quote: [" + sb.toString() + "]");
} else {
System.out.println("Text: [" + sb.toString() + "]");
}
}
哪个生成...
Text: [blah blah 123 ]
Quote: [hello]
Text: [ 234 ]
Quote: [world]
知道，我不知道你是如何存储结果的。我很想创建一些能够存储String结果并将它们添加到List的基本类，这样我就可以保持顺序并可能使用某种标志来确定它们的类型是...
答案 5 :(得分：0)
public String getNextQuote(int index, String sentence){
return sentence.substring(sentence.indexOf("\"", index + 1), sentence.indexOf("\"", index + 2));
}
用法：使用索引作为参数调用方法。此索引类似于您遇到的最后一个"的索引。
之后，它会返回下两个引号之间的所有内容。