Question

当我使用json将curl数据发布到API时 - 我没有得到任何输出。我想向收件人发送电子邮件邀请。

$url_send ="http://api.address.com/SendInvitation?";
$str_data = json_encode($data);

function sendPostData ($url, $post) {

    $ch = curl_init($url);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
    curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($post));

    return curl_exec($ch);
}

这是JSON $str_data

[
    {
        "authorizedKey"  : "abbad35c5c01-xxxx-xxx",
        "senderEmail"    : "myemail@yahoo.com",
        "recipientEmail" : "jaketalledo86@yahoo.com",
        "comment"        : "Invitation",
        "forceDebitCard" : "false"
    }
]

并且调用函数：

$response = sendPostData($url_send, $str_data);

这是API：https://api.payquicker.com/Help/Api/POST-api-SendInvitation

Answer 1

尝试添加curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
并将http_build_query($post)更改为$post

实施：

<?php

$data = array(
  "authorizedKey" => "abbad35c5c01-xxxx-xxx",
  "senderEmail" => "myemail@yahoo.com",
  "recipientEmail" => "jaketalledo86@yahoo.com",
  "comment" => "Invitation",
  "forceDebitCard" => "false"
);

$url_send ="http://api.payquicker.com/api/SendInvitation?authorizedKey=xxxxx";
$str_data = json_encode($data);

function sendPostData($url, $post){
  $ch = curl_init($url);
  curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");  
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
  curl_setopt($ch, CURLOPT_POSTFIELDS,$post);
  curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); 
  $result = curl_exec($ch);
  curl_close($ch);  // Seems like good practice
  return $result;
}

echo " " . sendPostData($url_send, $str_data);

?>

我得到的回应是：

{"success":false,"errorMessage":"Object reference not set to an instance of an object.","status":"N/A"}

但也许它适用于有效数据......

修改对于发布xml，除了字符串外，它与他们的网站相同：

$xml = ' <SendInvitationRequest xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.datacontract.org/2004/07/PQApi.Models"> <authorizedKey>80c587b9-caa9-4e56-8750-a34b17dba0a2</authorizedKey> <comment>sample string 4</comment> <forceDebitCard>true</forceDebitCard> <recipientEmail>sample string 3</recipientEmail> <senderEmail>sample string 2</senderEmail> </SendInvitationRequest>';

然后：

sendPostData($url_send, $xml)

Answer 2

您必须添加标题：

$headers= array('Accept: application/json','Content-Type: application/json');

和

curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);

否则......

HTTP状态415 - 不支持的媒体类型

......可能会发生。

Answer 3

您不需要像已经json_encode那样添加标题。只需print_r (curl_getinfo($ch));并在其中查看内容类型信息。

使用CURL将JSON数据发布到API

3 个答案: