Question

我正在使用spring mvc做servlet而我看不到我的网站。我在下面发布了我的web.xml，mvc-dispatcher-servlet.xml和控制器类。一切似乎都很好，但当我输入“localhost：8080”时，我得到404 http status The requested resource is not available。我错过了什么吗？

的web.xml：

<web-app version="2.4"
         xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
    http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

    <display-name>Weather</display-name>
    <servlet>
        <servlet-name>mvc-dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>
</web-app>

MVC-调度-servlet.xml中：

<context:component-scan base-package="com.springapp.mvc"/>

<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="prefix" value="/WEB-INF/pages/"/>
    <property name="suffix" value=".jsp"/>
</bean>

<jpa:repositories base-package="com.springapp.mvc"/>

<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean">
    <property name="persistenceUnitName" value="defaultPersistenceUnit"/>
</bean>

<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
    <property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>

<tx:annotation-driven transaction-manager="transactionManager"/>
<mvc:annotation-driven />

控制器类：

@Controller
public class HomeController
{
    Weather weather;

    @RequestMapping(value = "/", method = RequestMethod.GET)
    public String infoWeather(ModelMap model, HttpServletRequest req) {

        if (!model.containsAttribute("location") && !model.containsAttribute("weather")) {
            Language.getInstance().setLanguage(LanguageManager.getLanguage(new Locale(System.getProperty("user.language"))));
            Location location = LocationManager.getLocation(req);
            model.addAttribute("location", location);
            weather = WeatherManager.getWeather(location);
            model.addAttribute("weather", weather);
        }

        if (!model.containsAttribute("destination"))
            model.addAttribute("destination", new Destination());

        return "index";
    }

    @RequestMapping(value = "/search", method = RequestMethod.POST)
    public String findDestination(@ModelAttribute("destination") Destination destination, BindingResult result, RedirectAttributes redirectAttrs) {
        destination = DestinationManager.getDestination(destination.getAddress());
        weather = WeatherManager.getWeather(destination);
        redirectAttrs.addFlashAttribute("weather", weather);
        return "redirect:/";
    }
}

Answer 1

我在这里看到以下几点，需要修复：

在tomcat webapp目录中部署应用程序后，URL应为http://localhost:8080/<web-app-name>/<your servlet>
或者，您可以添加欢迎页面并检查它是否正常工作。为此，您需要在web-xml中添加欢迎页面设置。请参阅This post了解相关信息。

如果这不起作用，请与您部署的战争共享您的tomcat目录树;和war文件目录结构

注意：您应该能够使用zip实用程序扩展战争。

为什么我看不到我的网站，并获得HTTP状态404？

1 个答案: