我有一个关于如何配置我的python记录器的问题。您可以在下面看到我当前设置的记录器。 (http://docs.python.org/2/howto/logging-cookbook.html)
logger = logging.getLogger("someName")
logger.setLevel(logging.DEBUG)
fh = logging.FileHandler("./log/log.out", "w")
fh.setLevel(logging.DEBUG)
ch = logging.StreamHandler(sys.stderr)
ch.setLevel(logging.ERROR)
frm = logging.Formatter('%(asctime)s,%(msecs)d %(name)s %(levelname)s %(message)s','H:%M:%S')
fh.setFormatter(frm)
ch.setFormatter(frm)
logger.addHandler(fh)
logger.addHandler(ch)
是否有办法以这样的方式配置记录器:它还会写出如下所示的错误消息:
print a
>>> NameError: global name 'a' is not defined
非常感谢你的帮助。
答案 0 :(得分:5)
将您的代码包裹在try:
,except Exception:
块中并致电logger.exception()
:
try:
print a
except Exception:
logger.exception('Oops, something went wrong')
您可以向其添加raise
语句以重新引发捕获的异常。
演示:
>>> import logging
>>> logging.basicConfig()
>>> logger = logging.getLogger()
>>> def foo():
... print a
...
>>> def bar(i=0):
... if i < 3:
... bar(i + 1)
... else:
... foo()
...
>>> def baz():
... try:
... bar()
... except Exception:
... logger.exception('Oops, something went wrong')
...
>>> def spam(): baz()
...
>>> spam()
ERROR:root:Oops, something went wrong
Traceback (most recent call last):
File "<stdin>", line 3, in baz
File "<stdin>", line 3, in bar
File "<stdin>", line 3, in bar
File "<stdin>", line 3, in bar
File "<stdin>", line 5, in bar
File "<stdin>", line 2, in foo
NameError: global name 'a' is not defined
logging
模块记录了回溯,而不是我的交互式Python会话。
回溯从try
块引出到异常; spam()
函数是上面的例子,不包括在内。