我正在使用struts 2 MVC框架开发一个Web应用程序。我目前正在研究它的登录模块。我是这些技术的新手。我在维持会议方面遇到了问题。我希望如果某个人直接点击个人资料页面的网址(成功登录时打开的页面),那么他或她将被重定向回登录页面。此外,如果有人使用错误的凭据登录,则会再次将其重定向回登录页面。此外,如果他输入一些登录详细信息,则必须首先检查凭证,如果凭证r正确,则必须设置会话变量。在呈现配置文件页面之前,如果设置了会话变量,则会检查它们。如果仅设置了会话变量,则控件将传递到配置文件页面。
以下是我的登录表单代码loginPage.jsp:此页面显示用户的登录页面:
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<%@ taglib prefix="s" uri="/struts-tags" %>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>LOGIN PAGE</title>
</head>
<body>
<s:form action="login" method="post">
<s:textfield name="login.username" label="Username"/>
<s:password name="login.password" label="Password"/>
<s:submit value="SUBMIT" align="center"/>
<s:reset value="RESET" align="center"/>
</s:form>
</body>
</html>
现在是我的loginAction类:这是我的操作类,对应于在登录表单上单击登录按钮时产生的登录操作。
package com.view;
import java.util.Map;
import org.apache.struts2.interceptor.SessionAware;
import com.controller.LoginManager;
import com.model.Login;
import com.model.UserDetails;
public class LoginAction implements SessionAware{
private Login login;
private LoginManager loginManager;
private UserDetails userDetails;
Map<String,Object> map;
public LoginAction()
{
loginManager=new LoginManager();
}
public String loginLink()
{
return "loginClicked";
}
public String checkLogin()
{
try
{
//String loggedInUsername=null;
System.out.println("---------"+login.getUsername());
/*if(map.containsKey("username"))
{
loggedInUsername=(String)map.get("username");
}*/
userDetails=loginManager.check(login);
/*if(loggedInUsername!=null && loggedInUsername==userDetails.getUsername())
{
return "loginSuccess";
}*/
if(userDetails!=null && userDetails.getUsername()!=null)
{
map.put("login",true);
map.put("username",userDetails.getUsername());
map.put("name",userDetails.getName());
map.put("sex",userDetails.getSex());
map.put("email",userDetails.getEmail());
map.put("phoneno",userDetails.getPhone_no());
System.out.println("Inside session map creation that is Successful login");
return "loginSuccess";
}
else
{
System.out.println("Inside check login with invalid credentials");
return "loginClicked";
}
}catch(Exception ex)
{
System.out.println("Inside exception of checkLogin.");
return "loginClicked";
}
}
public void setLogin(Login login)
{
this.login=login;
}
public Login getLogin()
{
return login;
}
@Override
public void setSession(Map<String, Object> map) {
this.map=map;
}
}
loginManager类:此类处理数据库部分。在此课程中检查登录凭据。
package com.controller;
import org.hibernate.Query;
import org.hibernate.classic.Session;
//import java.util.List;
import com.model.Login;
import com.model.UserDetails;
import com.util.HibernateUtil;
public class LoginManager extends HibernateUtil{
UserDetails userDetails;
public UserDetails check(Login login)
{
Session session = HibernateUtil.getSessionFactory().getCurrentSession();
session.beginTransaction();
try
{
System.out.println("Inside try block to retrieve from db");
String hql="FROM UserDetails where username='"+login.getUsername()+"' and password='"+login.getPassword()+"' and role='U'";
Query query = session.createQuery(hql);
System.out.println("Query Created");
userDetails=(UserDetails)query.uniqueResult();
//System.out.println("Returned Username"+userDetails.getUsername());
//System.out.println("Returned Password"+userDetails.getPassword());
session.getTransaction().commit();
}catch(Exception ex){
System.out.println("Exception generated is "+ex.getMessage());
session.getTransaction().rollback();
userDetails=null;
ex.printStackTrace();
}
return userDetails;
}
}
下面是我的struts.xml文件:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
"http://struts.apache.org/dtds/struts-2.0.dtd">
<struts>
<constant name="struts.devMode" value="true" />
<package name="package2" extends="struts-default">
<interceptors>
<interceptor name="myinterceptor" class="interceptors.LoginInterceptor" />
<interceptor-stack name="myinterceptorSt">
<interceptor-ref name="myinterceptor" />
<interceptor-ref name="defaultStack" />
</interceptor-stack>
</interceptors>
<action name="registerLink" class="com.view.RegisterAction" method="registerLink">
<result name="registerLinkClicked">/registerPage1.jsp</result>
</action>
<action name="register" class="com.view.RegisterAction" method="addUser">
<result name="registered">/registrationSuccess.jsp</result>
</action>
<action name="login" class="com.view.LoginAction" method="checkLogin">
<interceptor-ref name="myinterceptorSt" />
<result name="loginSuccess" type="redirect">/profile.jsp</result>
<result name="loginFail">/loginFail.jsp</result>
<result name="loginClicked">/loginPage.jsp</result>
</action>
<action name="sessionCheck" class="com.view.SessionCheckAction">
<result name="sessionCheckSuccess"></result>
</action>
<action name="loginLink" class="com.view.LoginAction" method="loginLink">
<result name="loginClicked">/loginPage.jsp</result>
</action>
</package>
</struts>
任何人都可以帮我处理应该编写的拦截器代码,以实现上面指定的功能。
答案 0 :(得分:2)
我读了评论,正如Dave Newton所说,这是拦截器代码:
public class LoginInterceptor extends AbstractInterceptor {
@Override
public String intercept(final ActionInvocation invocation) throws Exception {
Map<String, Object> session = ActionContext.getContext().getSession();
String username = (String) session.get("username");//getting username from session
// If the user is already logged-in, then let the request through.
if (username != null) {
return invocation.invoke();
}
Object action = invocation.getAction(); // get which action class is called
// for the first action LoginAction interceptor will allow request to be forwarded.
if (action instanceof LoginAction) {
return invocation.invoke();
}
else {
return "notAuthorized";
}
}
}
现在,在struts.xml
<interceptors></interceptors>
中添加代码
<global-results>
<result name="notAuthorized">/loginPage.jsp</result>
</global-results>
此答案基于您的代码。我最好提到post 以下是一些可以帮助您的链接