Question

我有一个包含以下值的表。

gl_accountcode  gl_reference    gl_subledger_code   MOE
40000000003000  00001064        TOTDOO01    
40000000003102  00001064        TOTDOO01            60
40002073999807  00001064        TOTDOO01    
40000000003000  00025928        WATSEC01    
40000000003102  00025928        WATSEC01            60
40305558609795  00025928        WATSEC01            60

当子串（B.gl_accountcode，9,2）='60'作为条件1以及（B.gl_accountcode）='40000000003102'和子串（B.gl_accountcode，9时，我想用60填充MOE列） 2）='60'对于相同的GL参考作为条件2.

我为此示例选取了两个GL参考“00001064”和“00025928”。

当子串（B.gl_accountcode，9,2）不是'60'并且（B.gl_accountcode）='40000000003102'用于相同的GL参考时，我不想在MOE列中填充'60'，这似乎正在发生用下面的sql。

select 
RTRIM(LTRIM(B.gl_accountcode)) as 'GL AccountCode',
RTRIM(LTRIM(B.gl_reference)) as 'GL Reference',
RTRIM(LTRIM(B.gl_subledger_code)) as 'GL Subledger Code',
CASE 
WHEN substring(B.gl_accountcode,9,2) = '60' OR (LTRIM(RTRIM(B.gl_accountcode))) =       '40000000003102' THEN '60'
ELSE ''
END MOE 
from dbo.pronto_NZD_GLTransUnion B
where B.gl_reference in ( '00025928', '00001064')
order by B.gl_reference, B.gl_accountcode

我想我需要自己加入桌子，但我无法理解它。感谢您的帮助。

Answer 1

... 60当子串（B.gl_accountcode，9,2）='60'作为条件1时，以及当（B.gl_accountcode）='40000000003102'和子串（B.gl_accountcode，9,2）='时60'对于相同的GL参考作为条件2。

当子串（B.gl_accountcode，9,2）不是'60'且（B.gl_accountcode）='40000000003102'
时，我不想在MOE列中填充'60'

更容易说是......

60 when substring(x) = '60' OR (B.gl_accountcode = 'y' and substring(x) = '60') (...and not when (B.gl_accountcode = 'y' and substring(x) <> '60')

基本上是

substring(x) = '60'

所以你最后的陈述是：

select RTRIM(LTRIM(B.gl_accountcode)) as 'GL AccountCode', RTRIM(LTRIM(B.gl_reference)) as 'GL Reference', RTRIM(LTRIM(B.gl_subledger_code)) as 'GL Subledger Code', CASE WHEN substring(B.gl_accountcode,9,2) = '60' THEN '60' ELSE '' END MOE from pronto_NZD_GLTransUnion B where B.gl_reference in ( '00025928', '00001064') order by B.gl_reference, B.gl_accountcode

编辑：当我在等待你想要的结果时，这可能是你想要的吗？

select 
RTRIM(LTRIM(B.gl_accountcode)) as 'GL AccountCode',
RTRIM(LTRIM(B.gl_reference)) as 'GL Reference',
RTRIM(LTRIM(B.gl_subledger_code)) as 'GL Subledger Code',
CASE 
WHEN substring(B.gl_accountcode,9,2) = '60' THEN '60'
WHEN gl_accountcode = '40000000003102' AND EXISTS (SELECT 1 FROM pronto_NZD_GLTransUnion a WHERE substring(a.gl_accountcode,9,2) = '60' AND a.gl_reference = B.gl_reference) THEN '60'
ELSE ''
END MOE 
from pronto_NZD_GLTransUnion B
where B.gl_reference in ( '00025928', '00001064')
order by B.gl_reference, B.gl_accountcode

看到它在sqlfiddle

在基于派生列的其他列的值组合中构造值

1 个答案: