如何杀死它并行运行的子进程

Question

我催生了很多孩子

var spawn = require('child_process').spawn,
  newProcess1 = spawn('node', ['File1.js']),
  newProcess2 = spawn('node', ['File2.js']),
  newProcess3 = spawn('node', ['File3.js']);

将并行运行。如果newProcess1失败，则必须停止或杀死newProcess2和newProcess3（如果尚未启动）。

如何杀死子进程？

Answer 1

newProcess1.on('close', function (code) { 
  console.log('child process ' + newProcess1.pid + ' exited with code ' + code); 
  newProcess2.kill();
  newProcess3.kill();
});

http://nodejs.org/api/child_process.html