Question

我知道我从这个流程文件中发送的状态为'1'，因为我的JavaScript生效了。问题是我没有收到电子邮件。

<?php
//Retrieve form data. 
//GET - user submitted data using AJAX
//POST - in case user does not support javascript, we'll use POST instead
$name = ($_GET['name']) ? $_GET['name'] : $_POST['name'];
$email = ($_GET['email']) ?$_GET['email'] : $_POST['email'];
$comment = ($_GET['comment']) ?$_GET['comment'] : $_POST['comment'];
//flag to indicate which method it uses. If POST set it to 1
if ($_POST) $post=1;
//Simple server side validation for POST data, of course, 
//you should validate the email
if (!$name) $errors[count($errors)] = 'Please enter your name.';
if (!$email) $errors[count($errors)] = 'Please enter your email.'; 
if (!$comment) $errors[count($errors)] = 'Please enter your comment.'; 
//if the errors array is empty, send the mail
if (!$errors) {
    //recipient - change this to your name and email
    $to = 'myemail@gmail.com';    
    //sender
    $from = $name . ' <' . $email . '>';

    //subject and the html message
    $subject = 'Comment from ' . $name;    
    $message = '
    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" 
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
    <html xmlns="http://www.w3.org/1999/xhtml">
    <head></head>
    <body>
    <table>
        <tr><td>Name</td><td>' . $name . '</td></tr>
        <tr><td>Email</td><td>' . $email . '</td></tr>
        <tr><td>Comment</td><td>' . nl2br($comment) . '</td></tr>
    </table>
    </body>
    </html>';
    //send the mail
    $result = sendmail($to, $subject, $message, $from);

    //if POST was used, display the message straight away
    if ($_POST) {
        if ($result) echo 'Thank you! We have received your message.';
        else echo 'Sorry, unexpected error. Please try again later';

    //else if GET was used, return the boolean value so that 
    //ajax script can react accordingly
    //1 means success, 0 means failed
    } else {
        echo $result;    
    }
//if the errors array has values
} else {
    //display the errors message
    for ($i=0; $i<count($errors); $i++) echo $errors[$i] . '<br/>';
    echo '<a href="form.php">Back</a>';
    exit;
}
//Simple mail function with HTML header
function sendmail($to, $subject, $message, $from) {
    $headers = "MIME-Version: 1.0" . "\r\n";
    $headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n";
    $headers .= 'From: ' . $from . "\r\n";

    $result = mail($to,$subject,$message,$headers);

    if ($result) return 1;
    else return 0;
}
?>

Answer 1

你提到你正在使用GoDaddy。 GoDaddy要求您合法地设置发件人地址以匹配其发送的站点的域，或使用带验证的SMTP。

这种发送电子邮件的方法存在巨大的漏洞。垃圾邮件发送者可以通过插入其他收件人轻松覆盖发件人：标题。

我不确定你的应用程序计划是以邮件为中心的，但我建议使用像 PHPMailer 或 PEAR :: Mail 这样的软件包，因为它需要处理在更高级别为您处理电子邮件。这让您专注于应用程序的更重要部分。内置的PHP mail()功能的功能非常有限，当你尝试扩展你的邮件功能时，你会遇到很多基础mail()功能无法处理的路障。代表你的附加逻辑（附件，MIME类型等）会浮现在脑海中。

Answer 2

在测试邮件时，你可以直接测试它到你的服务器，php邮件有一个已经运行的功能。如果你在xampp本地测试它将不会发送，除非你已经在localhost中设置了php邮件程序。但对我来说，在服务器上测试它比在localhost中更好。

没有收到来自php的电子邮件

2 个答案: