Question

我有以下查询：

SELECT
    101 AS TeacherID
    ,s.ID
    ,s.First
    ,s.Last
FROM dbo.Students s
FOR XML PATH('Student'), ROOT('Students')

生成输出：

<Students>
  <Student>
    <TeacherID>101</TeacherID>
    <ID>14</ID>
    <First>Mark</First>
    <Last>Smith</Last>
  </Student>
  <Student>
    <TeacherID>101</TeacherID>
    <ID>15</ID>
    <First>Josephina</First>
    <Last>Hewitt</Last>
  </Student>
</Students>

我想将每个组分成自己的行（放入单个XMLFormat列）：

AdministratorID   AdministratorName   XMLFormat
------------------------------------------------------------------------------------------------------------------------------------
125               Bertha              <Student><TeacherID>101</TeacherID><ID>14</ID><First>Mark</First><Last>Smith</Last></Student>
125               Bertha              <Student><TeacherID>101</TeacherID><ID>15</ID><First>Josephina</First><Last>Hewitt</Last></Student>

我尝试使用表格和列别名方法：

SELECT  125 AS AdministratorID,
        'Bertha' AS AdministratorName,
        t.c AS XMLFormat
FROM 
(   
    SELECT
        101 AS TeacherID
        ,s.ID
        ,s.First
        ,s.Last
    FROM dbo.Students s
    FOR XML PATH('Student'), ROOT('Students')
) t(c)

但是此查询生成单行数据，整个XML位于单个XMLFormat字段中。

我认为我可能需要使用.nodes（）方法，但是当我将.nodes（'/ Students / Student'）添加到t（c）别名时，我得到''语法不正确'。'。< / p>

我想避免在使用.nodes（）方法之前将数据放入XML变量，因为文本可能很长。

Answer 1

select
    125 as AdministratorID,
    'Bertha' as AdministratorName,
    (
        select
            101 as TeacherID, s.ID, s.First, s.Last
        for xml path('Student'), type
    ) as XMLFormat
from dbo.Students s

将FOR XML PATH结果拆分为单独的行

1 个答案: