Question

从下表中可以看出，id为1的用户共有10个点我要做的是从表单$edit_points提交一个号码以循环并从用户1中减去这个数字可以是任何例如：

$ edit_points = 6
将从第一个记录中减去4 然后移到下一个并且只减去余数2
然后突破循环

UserID  | TotalPoints      
-------------------
 1      | 4        
 1      | 4      
 1      | 2      
 4      | 3        
 3      | 3       
 5      | 4

这是我到目前为止所得到的

$pointLeft = $edit_points;//sent from form    
while($point = mysqli_fetch_array($output)){

if($pointLeft > $point["TotalPoints"]){//if pointsLeft more than this record
$remainder =  $pointLeft-$point["TotalPoints"];//get remainder
$query2 = "UPDATE pointstable SET TotalPoints=0 WHERE UserID=".$UserID;
$output2 =  $mysqli->query($query2);

}elseif($pointLeft < $point["TotalPoints"]){

$remainder =  $point["TotalPoints"] - $pointLeft;   
$query2 = "UPDATE pointstable SET TotalPoints=".$remainder." WHERE UserID=".$UserID;
$output2 =  $mysqli->query($query2);

}

$pointLeft = $remainder;

}

它适用于某一点，似乎用剩余的最后一个值填充所有记录我已经尝试过break并将if（$ pointLeft＆lt; = 0）放在第一个if上面但都没有效果任何帮助？或者更好的方法，最好使用php

Answer 1

感谢Marty
修改后的代码
我现在使用了一个唯一的ID PointID

$poinstLeft = $edit_points; //sent from form

while($point = mysqli_fetch_array($output)){
    //if pointsLeft more than this record
    if($poinstLeft >= $point["TotalPoints"]){
        //get remainder
        echo $poinstLeft." ";
        $remainder =  $poinstLeft-$point["TotalPoints"];
        $query2 = "UPDATE pointstable SET TotalPoints=0 WHERE UserID=".$UserID." AND PointID=".$point["PointID"];

        $output2 =  $mysqli->query($query2);
        // Calculate new pointsleft
        $poinstLeft = $remainder;

    } elseif ($poinstLeft < $point["TotalPoints"]){
        $remainder =  $point["TotalPoints"] - $poinstLeft;
        echo $poinstLeft." ";
        $query2 = "UPDATE pointstable SET TotalPoints=".$remainder." WHERE UserID=".$UserID." AND PointID=".$point["PointID"] ;
        $output2 =  $mysqli->query($query2);
        // Here, your remainder is different from the upper half of your if-function!
        // So, you don't have to recalculate pointsleft... It's just:
        $poinstLeft = 0;

        // Break the while loop:
     break 2;
    }


}

使用变量和更新变量更新表中的数字

1 个答案: