Question

我有一个查询，它会生成有关已发布检查的详细信息行。在最终输出中，数据全部连接并放入一列（长话短说，它需要从Infomaker运行并导出到没有分隔的文本）。

无论如何，在这些行的末尾，我需要一个摘要行，其中包含两个值，这两个值是前一行中使用的详细信息的总和，以及其他硬编码的值。最后一行也需要连接到一列，并显示在所有细节行之后。

摘要行应如何与括号中的计算值一起显示的示例：

00123456789999999999940[CHECK AMOUNT SUMMARY][TOTAL NUMBER OF CHECKS (ROWS)]000

同样，不允许使用空格，制表符或任何其他分隔符。

我很难理解如何实现这一目标。我有使用UNION的建议，但我不确定如何在这种情况下做到这一点。

当前查询：

declare @checkDate date = '08/30/13'

select 
record = (
-- Checking account number (Record positions 1-9)
cast(cna.BANK_ACCT_NUM as varchar(9)) +    

-- Check number (Record positions 10-19) -- must always be nine characters  
(case 
    when LEN(cr.CHECK_NUM_NUMERIC) = 1 
    then '00000000'
    when LEN(cr.CHECK_NUM_NUMERIC) = 2 
    then '0000000' 
    when LEN(cr.CHECK_NUM_NUMERIC) = 3 
    then '000000'
    when LEN(cr.CHECK_NUM_NUMERIC) = 4 
    then '00000'
    when LEN(cr.CHECK_NUM_NUMERIC) = 5 
    then '0000'
    when LEN(cr.CHECK_NUM_NUMERIC) = 6 
    then '000'
    when LEN(cr.CHECK_NUM_NUMERIC) = 7 
    then '00'
    when LEN(cr.CHECK_NUM_NUMERIC) = 8 
    then '0'
    else ''
    end + cast(cr.CHECK_NUM_NUMERIC as varchar(9))) +

-- Record positions 20-21 - as determined by the bank
'20' +

-- Check amount (Record positions 22-31) -- must always be 10 characters
(case 
    when LEN(cr.CHECK_AMT) = 1 
    then '000000000'
    when LEN(cr.CHECK_AMT) = 2 
    then '00000000' 
    when LEN(cr.CHECK_AMT) = 3 
    then '0000000'
    when LEN(cr.CHECK_AMT) = 4 
    then '000000'
    when LEN(cr.CHECK_AMT) = 5 
    then '00000'
    when LEN(cr.CHECK_AMT) = 6 
    then '0000'
    when LEN(cr.CHECK_AMT) = 7 
    then '000'
    when LEN(cr.CHECK_AMT) = 8 
    then '00'
    when LEN(cr.CHECK_AMT) = 9 
    then '0'
    else ''
    end + cast(REPLACE(cr.CHECK_AMT,'.','') as varchar(10))) +

-- Date issued (MMDDYY)(Record positions 32-37)
cast(REPLACE(convert(char(10),cr.CHECK_DTE,101), '/', '') as varchar(10)) +   

-- Record positions 38-40 - as determined by the bank
'000' +

-- Payee information line 1 (Record positions 41-90)
cr.CHECK_NAME)

from chk_num_alpha_ctl cna,   
chk_reconciliation cr 
where ( cr.check_num_alpha = cna.check_num_alpha ) and  
( ( cr.check_rtn_void_dte is null ) AND  
( cr.check_dte = @checkDate ) ) AND  
( cna.bank_acct_num = 'xxxx-xxxx' )   
order by cr.check_dte ASC

Answer 1

- 首先，您可以使用此类型的“right-justify-zero-fill”语句简化查询（如果多于或少于9个字符，则调整）：

select right('000000000' + cast(cr.CHECK_NUM_NUMERIC as varchar(9)),9)

- 然后尝试这样的事情（我无法测试它，所以可能会有一些调整）：

UNION
select '00123456789999999999940' 
+ right('000000000' + cast(sum(cr.CHECK_AMT) as varchar(9)),9) 
+ right('000000000' + cast(count(cr.CHECK_AMT) as varchar(9)),9) 
+ '000'
from chk_num_alpha_ctl cna,   
chk_reconciliation cr 
where ( cr.check_num_alpha = cna.check_num_alpha ) and  
( ( cr.check_rtn_void_dte is null ) AND  
( cr.check_dte = @checkDate ) ) AND  
( cna.bank_acct_num = 'xxxx-xxxx' )   
GROUP BY cr.check_dte 
order by cr.check_dte ASC

SQL汇总最后一行中的数据

1 个答案: