Question

我有一个“上传”视图，一旦填写表格并认为有效，就会创建模型的实例：

...
from CrossStitch.models import Pattern

def upload(request):
    if request.method == 'POST':
        form = UploadFileForm(request.POST, request.FILES)
        if form.is_valid():
            newpattern = Pattern(imagefile = request.FILES['pattern'],filename = request.POST['title'])
            return HttpResponseRedirect(reverse('configure', args=newpattern))
                                                                ^^
    else:
        form = UploadFileForm()
...

如上所示py向上箭头，我想将我的模型实例传递给下一个视图。配置视图如下：

def configure(request, pattern):
...

我的两个观点都有这样的网址：

url(r'^upload/$','CrossStitch.views.upload', name='upload'),
url(r'^configure/$','CrossStitch.views.configure', name='configure'),

但是，我收到了这个错误：

TypeError at /CrossStitch/upload/
_reverse_with_prefix() argument after * must be a sequence, not Pattern
Request Method: POST
Request URL:    http://127.0.0.1:8000/CrossStitch/upload/
Django Version: 1.4.5
Exception Type: TypeError
Exception Value:    
_reverse_with_prefix() argument after * must be a sequence, not Pattern
Exception Location: /usr/lib/python2.7/dist-packages/django/core/urlresolvers.py in reverse, line 476
Python Executable:  /usr/bin/python
Python Version: 2.7.3
Python Path:    
['/home/stacey/work/Django/StaceyAnne',
 '/usr/lib/python2.7',
 '/usr/lib/python2.7/plat-linux2',
 '/usr/lib/python2.7/lib-tk',
 '/usr/lib/python2.7/lib-old',
 '/usr/lib/python2.7/lib-dynload',
 '/usr/local/lib/python2.7/dist-packages',
 '/usr/lib/python2.7/dist-packages',
 '/usr/lib/python2.7/dist-packages/PIL',
 '/usr/lib/python2.7/dist-packages/gtk-2.0',
 '/usr/lib/pymodules/python2.7']
Server time:    Wed, 4 Sep 2013 15:22:12 +0200

如何正确地将我的对象实例从一个视图传递到另一个视图？

Answer 1

args is an iterative的reverse关键字参数。你应该通过，例如改为列表或元组。

但是，在您的情况下，pattern的{{1}}参数不应该是一个对象。在URL配置中，正则表达式应包含您要配置的模式的标识符，如part 3 of this tutorial中所述。这种方式在configure中，您可以按ID获取模式，configure调用看起来像这样：reverse。

通过HttpResponseRedirect将对象从django中的一个视图传递到另一个视图

1 个答案: