我想使用两个字符串(如果nameSpace存在,我想要t know their content) to create two nameSpace.And i don
想创建一个新字符串。
这是我的代码:
function createNameSpace(nameSpace)
{
var spaceArr = nameSpace.split(".");
var curSpace = window;
//judge if this nameSpace exists.
var i;
for(i in spaceArr)
{
curSpace = curSpace[spaceArr[i]];
if(curSpace)
window.alert("nameSpace1:" + nameSpace + "\ncurSpace do exists:" + curSpace + "\ni:" + i + "\nspaceArr[i]:" + spaceArr[i] + "|");
else
{
curSpace = {};
window.alert("nameSpace1:" + nameSpace + "\ncurSpace not found:" + curSpace + "\ni:" + i + "\nspaceArr[i]:" + spaceArr[i] + "|");
break;
}
}
//now curSpace must have been created.
i++;
//window.alert("nameSpace2:" + nameSpace + "\ni:" + i + "\nspaceArr.length:" + spaceArr.length);
//create the nameSpace
for(;i < spaceArr.length; i++)
{
//window.alert("nameSpace2:" + nameSpace + "\ni:" + i + "\nspaceArr.length:" + spaceArr.length);
if(i == 0)
{
window[spaceArr[i]] = {};
curSpace = window[spaceArr[i]];
}
else
{
//window.alert("nameSpace3:" + nameSpace + "\ncurSpace[spaceArr[i]]:" + curSpace[spaceArr[i]]);
curSpace[spaceArr[i]] = {};
curSpace = curSpace[spaceArr[i]];
}
}
return curSpace;
}
问题是,如果我将“myTest.myNameSpace”和“myTest.monaNameSpace”发送到此函数中,它会发出“curSpace not found”,当我发送“myTest.monaNameSpace”时应该是“curSpace do exists:” “。我不知道错误在哪里,有人可以告诉我吗?
答案 0 :(得分:0)
我认为你的算法有点复杂。我稍微重构了一下并添加了测试并验证它在控制台中工作。我也多次写过这段代码,所以我很确定我已达到你的要求
function createNameSpace(nameSpace)
{
var spaceArr = nameSpace.split(".");
var curSpace = window;
//judge if this nameSpace exists.
var i = 0;
for(i = 0;i < spaceArr.length; i++)
{
var next = spaceArr[i];
console.log(curSpace, next);
if(curSpace[next] == undefined)
{
curSpace[next] = {};
curSpace = curSpace[next]
}
else
{
curSpace = curSpace[next];
}
}
return curSpace;
}
createNameSpace("myTest.myNameSpace");
console.log(myTest.myNameSpace);
myTest.myNameSpace.myName = "Leat Hakkor";
createNameSpace("myTest.monaNameSpace");
console.log(myTest.monaNameSpace);
console.log(myTest.myNameSpace.myName);