我一直试图解析这个无钥匙的json数组。我知道有很多关于如何解析json数组的教程,但它们总是遵循相同的模式。我在这里有这个网站,我试图解析并显示文本。 http://ec2-54-213-155-95.us-west-2.compute.amazonaws.com/notices.php
DefaultHttpClient httpclient = new DefaultHttpClient(new BasicHttpParams());
HttpPost httppost = new HttpPost("http://ec2-54-213-155-95.us-west-2.compute.amazonaws.com/notices.php");
// Depends on your web service
httppost.setHeader("Content-type", "application/json");
InputStream inputStream = null;
String result = null;
try {
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
inputStream = entity.getContent();
// json is UTF-8 by default
BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream, "UTF-8"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null)
{
sb.append(line + "\n");
}
result = sb.toString();
} catch (Exception e) {
// Oops
}
finally {
try{if(inputStream != null)inputStream.close();}catch(Exception squish){}
}
JSONObject jObject = new JSONObject(result);
}
我目前被困在这里。我该怎么办?
答案 0 :(得分:1)
这应该不是那么困难。见下面的代码。 寻找语法错误并处理异常,我只需输入它。
JSONArray jsonArray = jObject.getJSONArray("notices");
for(int i = 0; i < jsonArray.length(); i++) {
String string = jsonArray.getString(i);
Log.d("TAG", string); // do whatever you want with "string"
}