我正在尝试使用以下代码使用openCV 2.4.6.1修改和编写一些视频:
cv::VideoCapture capture( video_filename );
// Check if the capture object successfully initialized
if ( !capture.isOpened() )
{
printf( "Failed to load video, exiting.\n" );
return -1;
}
cv::Mat frame, cropped_img;
cv::Rect ROI( OFFSET_X, OFFSET_Y, WIDTH, HEIGHT );
int fourcc = static_cast<int>(capture.get(CV_CAP_PROP_FOURCC));
double fps = 30;
cv::Size frame_size( RADIUS, (int) 2*PI*RADIUS );
video_filename = "test.avi";
cv::VideoWriter writer( video_filename, fourcc, fps, frame_size );
if ( !writer.isOpened() && save )
{
printf("Failed to initialize video writer, unable to save video!\n");
}
while(true)
{
if ( !capture.read(frame) )
{
printf("Failed to read next frame, exiting.\n");
break;
}
// select the region of interest in the frame
cropped_img = frame( ROI );
// display the image and wait
imshow("cropped", cropped_img);
// if we are saving video, write the unwrapped image
if (save)
{
writer.write( cropped_img );
}
char key = cv::waitKey(30);
当我尝试使用VLC运行输出视频'test.avi'时,我得到以下错误:avidemux错误:没有为轨道0设置关键帧。我正在使用Ubuntu 13.04,我尝试使用编码的视频使用MPEG-4和libx264。我认为修复应该是直截了当的,但找不到任何指导。实际代码位于https://github.com/benselby/robot_nav/tree/master/video_unwrap。提前谢谢!
答案 0 :(得分:3)
[PYTHON]除了分辨率不匹配外,还可能存在每秒帧数不匹配的情况。就我而言,分辨率设置正确,但问题出在fps上。检查VideoCapture对象正在读取的每秒帧数,它显示为30.0,但如果我将VideoWriter对象的fps设置为30.0,则在VLC中抛出相同的错误。而不是将其设置为30.0,您可以通过将其设置为30来解决错误。
P.S。您可以使用宽度cap.get(3)
,高度cap.get(4)
和捕捉while / for循环内的fps cap.get(5)
来检查分辨率和录制时的fps。
完整代码如下:
import numpy as np
import cv2 as cv2
cap = cv2.VideoCapture(0)
#Define Codec and create a VideoWriter Object
fourcc = cv2.VideoWriter_fourcc('X','V','I','D')
#30.0 in the below line doesn't work while 30 does work.
out = cv2.VideoWriter('output.mp4', fourcc, 30, (640, 480))
while(True):
ret, frame = cap.read()
colored_frame = cv2.cvtColor(frame, cv2.COLOR_BGR2BGRA)
print('Width = ', cap.get(3),' Height = ', cap.get(4),' fps = ', cap.get(5))
out.write(colored_frame)
cv2.imshow('frame', colored_frame)
if cv2.waitKey(1) & 0xFF == ord('q'):
break
cap.release()
out.release()
cv2.destroyAllWindows()
可以在此处获取有关可以检查所有属性的完整文档(C ++):propId OpenCV Documentation
答案 1 :(得分:1)
这似乎是所写帧和打开的VideoWriter对象之间大小不匹配的问题。当我尝试将一系列经过调整的图像从我的网络摄像头写入视频输出时,我遇到了这个问题。当我删除调整大小步骤并从初始测试框架中抓取尺寸时,一切都运行良好。
为了修复我的调整大小代码,我基本上通过处理运行了一个测试框架,然后在创建VideoWriter对象时拉大小:
#include <cassert>
#include <iostream>
#include <time.h>
#include "opencv2/opencv.hpp"
using namespace cv;
int main()
{
VideoCapture cap(0);
assert(cap.isOpened());
Mat testFrame;
cap >> testFrame;
Mat testDown;
resize(testFrame, testDown, Size(), 0.5, 0.5, INTER_NEAREST);
bool ret = imwrite("test.png", testDown);
assert(ret);
Size outSize = Size(testDown.cols, testDown.rows);
VideoWriter outVid("test.avi", CV_FOURCC('M','P','4','2'),1,outSize,true);
assert(outVid.isOpened());
for (int i = 0; i < 10; ++i) {
Mat frame;
cap >> frame;
std::cout << "Grabbed frame" << std::endl;
Mat down;
resize(frame, down, Size(), 0.5, 0.5, INTER_NEAREST);
//bool ret = imwrite("test.png", down);
//assert(ret);
outVid << down;
std::cout << "Wrote frame" << std::endl;
struct timespec tim, tim2;
tim.tv_sec = 1;
tim.tv_nsec = 0;
nanosleep(&tim, &tim2);
}
}
我的猜测是你的问题在于大小计算:
cv::Size frame_size( RADIUS, (int) 2*PI*RADIUS );
我不确定你的帧来自哪里(即如何设置捕获),但可能在舍入或其他地方你的大小搞砸了。我建议做一些与我上面的解决方案类似的事情。