Question

我的系统中安装了SQL Server数据库和Activemq。我试图创建端点来监听activemq所在的端口。该港口是61617

CREATE ENDPOINT InstInitiatorEndpoint
STATE = STARTED
AS TCP ( LISTENER_PORT = 61617 )
FOR SERVICE_BROKER (AUTHENTICATION = WINDOWS );
GO

但它会导致错误：

由于以下错误，Service Broker端点无法侦听连接：'10013（尝试以其访问权限禁止的方式访问套接字。）'。

由于activemq已在同一端口上运行。我应该给不同的端口吗？如果我给出不同的端口号，那么它正在成功执行。但基本上LISTENER_PORT=61617表示端点侦听端口61617，不是吗？任何人都可以澄清我的怀疑吗？

修改我们假设我已经创建了端点，消息类型，合同，队列和服务，如下所示

 CREATE MESSAGE TYPE RequestMessage
   VALIDATION = WELL_FORMED_XML;
 CREATE MESSAGE TYPE ReplyMessage
   VALIDATION = WELL_FORMED_XML;
 GO



 CREATE CONTRACT SimpleContract
  (RequestMessage
     SENT BY INITIATOR,
   ReplyMessage
     SENT BY TARGET
  );
 GO


  CREATE QUEUE InstInitiatorQueue;

 CREATE SERVICE InitiatorService
   AUTHORIZATION InitiatorUser
   ON QUEUE InstInitiatorQueue;
 GO



DECLARE @Cmd NVARCHAR(4000);

SET @Cmd = N'USE InstInitiatorDB;
CREATE ROUTE InstTargetRoute
WITH SERVICE_NAME =
   N''TargetService'',
 ADDRESS = N''TCP://localhost:61617'';';

EXEC (@Cmd);

DECLARE @Cmd NVARCHAR(4000);
SET @Cmd = N'USE msdb
CREATE ROUTE InstInitiatorRoute
WITH SERVICE_NAME =
   N''InitiatorService'',
 ADDRESS = N''LOCAL''';

 EXEC (@Cmd);
GO

CREATE REMOTE SERVICE BINDING TargetBinding
  TO SERVICE
     N'TargetService'
  WITH USER = TargetUser;

GO

现在我为对话创建句柄

 DECLARE @InitDlgHandle UNIQUEIDENTIFIER;
 DECLARE @RequestMsg NVARCHAR(100);

 BEGIN TRANSACTION;

 BEGIN DIALOG @InitDlgHandle
 FROM SERVICE InitiatorService
 TO SERVICE N'TargetService'
 ON CONTRACT SimpleContract
 WITH
     ENCRYPTION = ON;

 SELECT @RequestMsg = N'<RequestMsg>Message for Target service434.</RequestMsg>';

 SEND ON CONVERSATION @InitDlgHandle
 MESSAGE TYPE RequestMessage
 (@RequestMsg);

SELECT @RequestMsg AS SentRequestMsg;

COMMIT TRANSACTION;
GO

此处如果您看到我尝试了两个SQL Server实例之间的对话示例，以便在SQL Server和activemq之间进行对话。我需要指定服务器到服务器的通信，因为我需要指定服务（启动器）来服务（目标）。我知道启动器服务器是sql server，但我不知道activemq的服务。我应该在数据库端的句柄对话中指定activemq的服务是什么？

从SQL Server到外部应用程序的消息（activemq）

0 个答案: