Question

我需要按年龄和婚姻状况计算个人的频率，所以通常我会使用：

    table(age, marital_status)

然而，在采样数据后，每个人的体重都不同。如何将其纳入我的频率表？

Answer 1

您可以使用包svytable中的功能survey或wtd.table中的rgrs。

编辑： rgrs现在称为questionr：

df <- data.frame(var = c("A", "A", "B", "B"), wt = c(30, 10, 20, 40))

library(questionr)
wtd.table(x = df$var, weights = df$wt)
#  A  B 
# 40 60

dplyr：

也可以

library(dplyr)
count(x = df, var, wt = wt)
# # A tibble: 2 x 2
#        var     n
#     <fctr> <dbl>
#   1      A    40
#   2      B    60

Answer 2

为了完整起见，使用基础 R：

df <- data.frame(var = c("A", "A", "B", "B"), wt = c(30, 10, 20, 40))

aggregate(x = list("wt" = df$wt), by = list("var" = df$var), FUN = sum)

<块引用>

var wt
1 A 40
2 B 60

或者使用不那么麻烦的公式符号：

aggregate(wt ~ var, data = df, FUN = sum)

<块引用>

var wt
1 A 40
2 B 60

Answer 3

软件包expss中的另一个解决方案：

    df <- data.frame(var = c("A", "A", "B", "B"), wt = c(30, 10, 20, 40))
    
    library(expss)
    
    fre(df$var, weight = df$wt)

 | df$var | Count | Valid percent | Percent | Responses, % | Cumulative responses, % |
 | ------ | ----- | ------------- | ------- | ------------ | ----------------------- |
 |      A |    40 |            40 |      40 |           40 |                      40 |
 |      B |    60 |            60 |      60 |           60 |                     100 |
 | #Total |   100 |           100 |     100 |          100 |                         |
 |   <NA> |     0 |               |       0 |              |                         |

Answer 4

您还可以使用freqweights包中的tablefreq：

df <- data.frame(var = c("A", "A", "B", "B"), wt = c(30, 10, 20, 40))

library(freqweights)

tablefreq(df, "var", "wt")

A tibble: 2 x 2
var    freq
<fct> <dbl>
1 A        40
2 B        60

Answer 5

您可以使用data.table：

# using the same data as Victorp
setDT(df)[, .(n = sum(wt)), var] 

   var  n
1:   A 40
2:   B 60

Answer 6

使用包权重和函数 wpct

require(weights)
df <- data.frame(var = c("A", "A", "B", "B"), wt = c(30, 10, 20, 40))
wpct(df$var, df$wt)

 A   B 
0.4 0.6

R中加权数据的频率表

6 个答案: