Question

我正在尝试根据categories_id在第二个表中是否等于90但是获得未知列错误来更新1列。

这是我的sql：

UPDATE products SET qty='20' 
WHERE products.products_id = products_to_categories.products_id AND products_to_categories.categories_id = '90'

我得到的错误是

'where子句'

中的未知列'products_to_categories.products_id'

Answer 1

在SQL中，您必须使用from（或update或delete）语句引入表名。你的意思是：

UPDATE products
    SET qty = '20' 
    WHERE exists (select 1
                  from products_to_categories ptc
                  where ptc.products_id = products.products_id AND
                        ptc.categories_id = '90'
                 );

另一种方法是使用连接：

UPDATE products p join
       products_to_categories ptc
       on  ptc.products_id = products.products_id AND
           ptc.categories_id = '90'
    SET p.qty = '20';

如果有多个匹配项，则效果会更好。

Answer 2

您不能在UPDATE命令中组合两个表。使用子查询。

UPDATE products SET qty='20' 
WHERE products.products_id IN (SELECT `ptc`.`products_id`
                               FROM   `products_to_categories` `ptc`
                               WHERE  `ptc`.categories_id = '90')

Answer 3

您需要在连接语句中包含该表，除非表已加入，否则无法找到products_to_categories.products_id。

UPDATE products a
       INNER JOIN products_to_categories b
             ON a.products_id = b.products_id
SET    a.qty = '20' 
WHERE  b.categories_id = '90'

Answer 4

您可以使用mysql的multiple table syntax：

UPDATE products
JOIN products_to_categories
  ON products.products_id = products_to_categories.products_id
  AND products_to_categories.categories_id = '90'
SET qty='20'

请参阅SQLFddile上查看的此查询语法。

Answer 5

UPDATE products p, products_to_categories pc
SET p.qty='20' 
WHERE p.products_id = pc.products_id AND pc.categories_id = '90'

<强> FIDDLE

更新语句给出未知列错误

5 个答案: