如果它们等于某个字符串，如何删除字符串的最后一个字符？

Question

如果最后三个字符等于"01x"？

，我如何修剪它们

例如，我有这个：

$stuff = array(
    "aaaaa01x",
    "aaaaa1",
    "aaaaa01x",
    "aaaaa01",
    "aaaaa01",
    "aaaaa01x"
    "aaaaa11"
);

我正在尝试输出：

$stuff = array(
    "aaaaa", // trimmed
    "aaaaa1",
    "aaaaa", // trimmed
    "aaaaa01",
    "aaaaa01",
    "aaaaa", // trimmed
    "aaaaa11"
);

我在使用trim()尝试执行此操作时遇到问题，因为trim()修剪了以三个字符中的任何一个结尾的任何字符串。

例如，trim($string, '01x');将从以这些字符结尾的任何字符串中删除"1"，"0"，"x"。我只想在字符串以“01x”结尾时修剪。

Answer 1

$stuff = array(
    "aaaaa01x",
    "aaaaa1",
    "aaaaa01x",
    "aaaaa01",
    "aaaaa01",
    "aaaaa01x",
    "aaaaa11"
);

for($i = 0; $i < count($stuff); $i ++)
{
    $stuff[$i] = (substr($stuff[$i], -3) == '01x' ? substr($stuff[$i], 0, -3) : $stuff[$i]);    
}

Answer 2

代码：

$stuff = array(
    "aaaaa01x",
    "aaaaa1",
    "aaaaa01x",
    "aaaaa01",
    "aaaaa01",
    "aaaaa01x",
    "aaaaa11"
);

foreach($stuff as $key => $thing) {
   if(substr($thing, -3, 3) == '01x')
      $stuff[$key] = trim($thing, '01x');
}

var_dump($stuff);

输出：

array(7) {
   [0]=> string(5) "aaaaa"
   [1]=> string(6) "aaaaa1"
   [2]=> string(5) "aaaaa"
   [3]=> string(7) "aaaaa01"
   [4]=> string(7) "aaaaa01"
   [5]=> string(5) "aaaaa"
   [6]=> string(7) "aaaaa11"
}

Answer 3

通过循环运行数组，并创建一个新数组。

$i = 0;
foreach($stuff as $s){
$stuff[$i] = preg_replace('/01x$/', '', $s);
$i++;
}

Answer 4

您可以使用strrpos()查找搜索字符串的最后位置。

$stuff = array(
    "aaaaa01x",
    "aaaaa1",
    "aaaaa01x",
    "aaaaa01",
    "aaaaa01",
    "aaaaa01x",
    "aaaaa11"
);

for ($i = 0; $i < count($stuff); $i++) {
    if (($pos = strrpos($stuff[$i], '01x')) !== FALSE) {
        $stuff[$i] = substr($stuff[$i], 0, $pos);
    }
}

print_r($stuff);