Question

我希望在用户想要注册时集成FILTER_VALIDATE_EMAIL过滤器。

我有这个输入：

<input type="text" name="email" maxlength="255" />

代码的某些部分：

$ email = strip_tags（mysql_real_escape_string（$ _ POST ['email']））;
$ email2 = mysql_query（“SELECT * FROM users WHERE email ='{$ email}'”）;

和此：

if(mysql_num_rows($email2) == 1)
{
echo "This email address is already in used.";
}

如果您需要更多代码，请告诉我们。谢谢！
这是我第一次使用MySQL，做得好！或其他验证电子邮件的方式，ofc。

Answer 1

如何使用的示例：

$email = "someone@example.com";

if(!filter_var($email, FILTER_VALIDATE_EMAIL)){
  echo "E-mail is not valid";//Handle not valid email
}else{
  $result = mysql_query("SELECT * FROM users WHERE email = '{$email}'");
  //handle $result of DB
}

From Manual

另请注意：自PHP 5.5.0起，不推荐使用Mysql_ *扩展，将来也会删除。相反，应该使用MySQLi或PDO_MySQL扩展。

有用的链接Why shouldn't I use mysql_* functions in PHP

Answer 2

请尝试以下代码：

$email = strip_tags(mysql_real_escape_string($_POST['email']));

if(filter_var($email, FILTER_VALIDATE_EMAIL)) { // Email is valid
    $result = mysql_query("SELECT * FROM users WHERE email = '{$email}'");

   if(mysql_num_rows($result)) {
      echo "This email address is already in used.";
    }
} else {
    echo "E-mail is not valid";
}

Answer 3

$email_a = 'mail_check@hotmail.com';
if (filter_var($email_a, FILTER_VALIDATE_EMAIL)) {
    echo "This (email_a) email address is considered valid."; 
   //reported as valid
} else {<br />
    echo "This email is invalid";
}

这是filter_var函数的一个示例，其中包含指定的过滤器（FILTER_VALIDATE_EMAIL）用法..

在注册脚本中集成FILTER_VALIDATE_EMAIL

3 个答案: