我需要将NSString传递给我的其他ViewController,但它会一直返回nil。
//prepareForSegue is called from didSelectRowAtIndexPath
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
if([[segue identifier] isEqualToString:@"chat"]) {
NSString *userName = (NSString *) [toUsersArray objectAtIndex:[self.chatsTableView indexPathForSelectedRow].row];
UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard" bundle:nil];
ChatViewController *chatViewController = [storyboard instantiateViewControllerWithIdentifier:@"ChatViewController"];
//[chatViewController setChatWithUser:userName]; EVEN TRIED:
chatViewController.chatWithUser = username;
}
}
这是我声明NSString的地方:
@interface ChatViewController : UIViewController <UITableViewDelegate, UITableViewDataSource, MessageDelegate> {
UITextField *messageField;
NSString *chatWithUser;
UITableView *chatTableView;
NSMutableArray *messagesArray;
}
@property (nonatomic,retain) IBOutlet UITextField *messageField;
@property (nonatomic,retain) NSString *chatWithUser;
@property (nonatomic,retain) IBOutlet UITableView *chatTableView;
- (IBAction) sendMessage;
@end
这里还是零:
@synthesize chatWithUser;
- (void)viewDidLoad {
[super viewDidLoad];
//DO STUFF WITH chatWithUser; ADDED BREAKPOINT AND chatWithUser = nil;
//ALSO TRIED viewWillAppear;
}
在这两个View Controller之间传递数据的正确方法是什么?我的变量保持无效。
答案 0 :(得分:2)
问题是你正在实例化一个新的ChatViewController,而不是segue要去的那个。您应该从segue的destinationViewController属性中获取该控制器。
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
if([[segue identifier] isEqualToString:@"chat"]) {
NSString *userName = (NSString *) [toUsersArray objectAtIndex:[self.chatsTableView indexPathForSelectedRow].row];
ChatViewController *chatViewController = segue.destinationViewController;
chatViewController.chatWithUser = username;
}
}
答案 1 :(得分:1)
//获取对目标视图控制器的引用
ChatViewController * ChatViewController = [segue destinationViewController];