Question

任何人都可以帮我这个代码吗？我无法弄清楚在compare_all_min ()和compare_all_max ()上使用什么参数。我的代码是：

while (count <= 10) {

    minimum = getMin ( item [count] );
    maximum = getMax ( item [count] );
    printf ( "Minimum is %d\n", &min );
    pritnf ( "Max: %d\n", &max );
    count++;
}

printf ( "Displaying summary:\n" );
least_num = compare_all_min (  );         //what argument do I  
greatest_num = compare_all_max (  );      //use on these two?
printf ( "The least number contained by the array is: %d\n", &least_num );
printf ( "The greatest number contained by the array is: %d\n", &greatest_num );

我无法弄清楚要使用什么参数，因为while循环将打印出10个最小数字和10个最大数字。 注意：基本上，compare_all_min ( )只是比较在while循环中获得的所有10个最小值，然后在这些值中获得最小值，compare_all_max ( )比较所有10个最大值值然后在这些数字中获得最大值。非常感谢。

Answer 1

假设你有10个元素的数组，那么将数组传递给函数

int min[10]={10,2,34..};//10 numbers

least_num = compare_all_min ( min );

包含三个数字的示例代码：

#include<stdio.h>
main()
{
int min[3]={10,2,34};//10 numbers
int least_num;
least_num = compare_all_min ( min );

printf("%d\n",least_num);
}

int compare_all_min (int *array)
{
int i,least;
least=array[0];

for(i=0;i<3;i++)
if(least > array[i])
least=array[i];
return least;

}

为函数分配参数

1 个答案: