Question

SELECT C.ClientCaseNumber,
       Sum(CASE
             WHEN CA.CaseActionDefinitionId IN (28, 29, 30) THEN 1
             ELSE 0
           END) AS [Wezwania],
       Sum(CASE
             WHEN CA.CaseActionDefinitionId IN (14, 21) THEN 1
             ELSE 0
           END) AS [Kontakt],
       Sum(CASE
             WHEN CA.CaseActionDefinitionId = 32 THEN 1
             ELSE 0
           END) AS [SMS],
       Sum(CASE
             WHEN CA.CaseActionDefinitionId = 44 THEN 1
             ELSE 0
           END) AS [Zgon],
       Sum(CASE
             WHEN CA.CaseActionDefinitionId = 49 THEN 1
             ELSE 0
           END) AS [Areszt],
       Sum(CASE
             WHEN CA.CaseActionDefinitionId = 37 THEN 1
             ELSE 0
           END) AS [Odmowa],
       Sum(CASE
             WHEN CA.CaseActionDefinitionId = 39 THEN 1
             ELSE 0
           END) AS [Podważa],
       Sum(CASE
             WHEN CA.CaseActionDefinitionId = 99 THEN 1
             ELSE 0
           END) AS [Ugoda],
       [Adres],
       [Numer],
       [Mail],
       [Powód]
FROM   (SELECT Notes AS [Adres]
        FROM   CaseActionHistory
        WHERE  CaseActionDefinitionId = 68
        UNION ALL
        SELECT Info AS [Numer]
        FROM   CaseActionHistory
        WHERE  CaseActionDefinitionId IN (54, 55, 56, 58,
                                          59, 60, 61, 62, 63)
        UNION ALL
        SELECT Notes AS [Mail]
        FROM   CaseActionHistory
        WHERE  CaseActionDefinitionId = 66
        UNION ALL
        SELECT Description AS [Powód]
        FROM   CaseActionDefinition
               JOIN CaseActionHistory AS C
                 ON DefinitionId = C.CaseActionDefinitionId
        WHERE  DefinitionId BETWEEN 70 AND 78) AS x
       INNER JOIN CaseDetails AS C
               ON x.CaseDetailId = C.CaseDetaislId
       INNER JOIN CaseActionHistory AS CA
               ON C.CaseDetailsId = CA.CaseDetailId
WHERE  C.ClientId = '11'
GROUP  BY C.ClientCaseNumber

我有这样的疑问。返回显示无效列“CaseDetailId，CaseDetailsId，Mail，Numer，Powód”的错误。

http://oi39.tinypic.com/2vwy44n.jpg

这或多或少是结果的样子。

ClientCaseNumber取自表CaseDetails 所有总和是添加到CaseActionHistory表的代码总和。 Notes / Info位于CaseActionHistory表中描述放在CaseActionDefinition表中。

在表之间有这样的联系：

CaseDetails.CaseDetailId = CaseActionHistory.CaseDetailsId

CaseActionHistory.CaseActionDefinitionId = CaseActionDefinition.DefinitionId

Answer 1

UNION子句不起作用。

此查询：

select Notes as [Adres] from CaseActionHistory where ...
UNION ALL
select Info as [Numer] from CaseActionHistory where ...
UNION ALL
select Notes as [Mail] from CaseActionHistory where ...
UNION ALL
select Description as [Powód] from CaseActionDefinition join CaseActionHistory ...

不会填充包含4列的表。相反，它将是一个包含一列的表，所有值都是一个接一个。该列的名称将取自第一个SELECT，即

如果第一个查询返回值1和2，
第二个查询返回值3和4
第三个查询返回值5和6
第四个查询返回值7和8

你不会得到：

Adres  | Numer | Mail | Powód
------------------------------
    1  |     3 |    5 |     7
    2  |     4 |    6 |     8

但你会得到：

Answer 2

您是否错过了这些字段中的别名“x”：

SELECT
C.ClientCaseNumber
,sum(case when CA.CaseActionDefinitionId in (28,29,30) then 1 else 0 end) as [Wezwania]
,sum(case when CA.CaseActionDefinitionId in (14,21) then 1 else 0 end) as [Kontakt]
,sum(case when CA.CaseActionDefinitionId = 32 then 1 else 0 end) as [SMS]
,sum(case when CA.CaseActionDefinitionId = 44 then 1 else 0 end) as [Zgon]
,sum(case when CA.CaseActionDefinitionId = 49 then 1 else 0 end) as [Areszt]
,sum(case when CA.CaseActionDefinitionId = 37 then 1 else 0 end) as [Odmowa]
,sum(case when CA.CaseActionDefinitionId = 39 then 1 else 0 end) as [Podważa]
,sum(case when CA.CaseActionDefinitionId = 99 then 1 else 0 end) as [Ugoda]
,x.[Adres]
,x.[Numer]
,x.[Mail]
,x.[Powód]

FROM
(select Notes as [Adres] from CaseActionHistory where CaseActionDefinitionId = 68
UNION ALL
select Info as [Numer] from CaseActionHistory where CaseActionDefinitionId in (54,55,56,58,59,60,61,62,63)
UNION ALL
select Notes as [Mail] from CaseActionHistory where CaseActionDefinitionId = 66
UNION ALL
select Description as [Powód] from CaseActionDefinition join CaseActionHistory as C on DefinitionId = C.CaseActionDefinitionId where DefinitionId between 70 and 78) 
AS x

inner join CaseDetails as C on x.CaseDetailId = C.CaseDetaislId
inner join CaseActionHistory as CA on C.CaseDetailsId = CA.CaseDetailId

where C.ClientId = '11'

GROUP by C.ClientCaseNumber

子选择＆amp;联合所有

2 个答案: