请帮我修复我的应用程序的这个脚本,我正在努力让链选择工作。 该脚本基本上从下拉列表中检查所选的下拉值,并在数据库中搜索值
JS:
<Script type="text/javascript">
$("#propinsi_id").change(function () {
var propinsi_id = {
propinsi_id: $("#propinsi_id").val()
};
$.Ajax({
type: "POST",
url: "<?php echo SITE_URL('Repair/select_fault')?>",
Data: propinsi_id,
success: function (msg) {
$('#city').html(msg);
}
});
});
</Script>
错误:
I caught this error
Uncaught TypeError: Object
function (selector, context) {
//The jQuery object is actually just the init constructor 'enhanced'
return new jQuery.fn.init(selector, context, rootjQuery);
}
has no method 'Ajax'
答案 0 :(得分:0)
此
$.Ajax({
需要小写
$.ajax({
我还会将Data:
更改为data:
答案 1 :(得分:0)
试试这个
<script type = "text/javascript" >
$("#propinsi_id").change(function(){
var propinsi_id = {propinsi_id:$("#propinsi_id").val()};
$.ajax({ //<---here
type: "POST" ,
url: "<?php echo SITE_URL('Repair/select_fault')?>" ,
data:propinsi_id, //<---here
success:function(msg) {
$('#city').html(msg);
}
});
});
</script>