Question

好的家伙来自这个帖子Rhino Evaluating a javascript object in Java我试图以不同的方式评估javascript。即没有defineClass，也没有正确评估Person对象。

有人可以帮帮我吗？

工作代码如下，

的Javascript

importPackage(Packages.com.testpkg);
defineClass("com.testpkg.Person");

var parser = new MyParser();

var myObject = new Person();
myObject.string1 = "Hello";
myObject.string2 = "World";
myObject.id = 1;
myObject.string4 = "Testing";
myObject.string3 = "Another Test";
try
{
   var returnStr = parser.PrintObj(myObject);
}
catch (e)
{
   print("An error occured");
}

人员类

public class Person extends ScriptableObject {

   private int id; 
   private String string1;
   private String string2;
   private String string3;

   public Person() {
       System.out.println("Person: Person Constructor");
   }

   public void jsConstructor() {
       System.out.println("Person: jsConstructor");
       this.string1 = "";
       this.string2 = "";
       this.id = 0;
   }

   public int getID() {
       return this.id;
   }

   public void jsSet_id(int value) {
       this.id = value;
   }

   public int jsGet_id() {
       return this.id;
   }

   public String jsGet_string1() {
       return this.string1;
   }

   public void jsSet_string1(String value) {
       this.string1 = value;
   }

   public String jsGet_string2() {
       return this.string2;
   }

   public void jsSet_string2(String value) {
       this.string2 = value;
   }

   public String jsGet_string3() {
       return this.string3;
   }

   public void jsSet_string3(String value) {
       this.string3 = value;
   }

   @Override
   public String toString() {
       return id + " " + string1 + " " + string2 + " " + string3;
   }

   @Override
   public String getClassName() {
       return "Person";
   }

}

MyParser类

public class MyParser {    
    public MyParser() {
        System.out.println("Entered constructor");
    }

    public String PrintObj(ScriptableObject obj) {
        Person pObj = (Person)Context.jsToJava(obj, Person.class);
        System.out.println("Printing p: " + pObj);
        return null;
    }
}

输出是，

Entered constructor
Person: Person Constructor
Person: jsConstructor
Printing p: 1 Hello World Another Test

现在的问题是我摆脱了defineClass。在使用（Rhapsody健康产品）的应用程序中实现的Rhino版本没有定义此方法。因此，我无法使用它。我使用另一种方法来加载类Person。如果我摆脱了defineClass，输出将是，

Entered constructor
Person: Person Constructor
Printing p: 0 null null null

请帮忙！

Answer 1

按照以下步骤修正了它。

Javascript（TestScript.js）

Person = com.testpkg.Person;
MyParser = com.testpkg.MyParser;
var myObject = Person.getInstance("myObject");
myObject.id = 1;
myObject.string1 = "Hello";
myObject.string2 = "World";
myObject.string3 = "Another Test";
myObject.string4 = "Testing";
try
{
   var parser = new MyParser();
   var returnStr = parser.PrintObj(myObject);
}
catch (e)
{
   print("An error occured");
}

人员类

package com.testpkg;
public class Person extends ScriptableObject {

   private int id; 
   private String string1;
   private String string2;
   private String string3;

   public Person() {
   }

   public void jsConstructor() {
       System.out.println("Person: jsConstructor");
       this.id = 0;
       this.string1 = "";
       this.string2 = "";
       this.string3 = "";
   }

   public int jsGet_id() {
       return this.id;
   }

   public void jsSet_id(int value) {
       this.id = value;
   }

   public String jsGet_string1() {
       return this.string1;
   }

   public void jsSet_string1(String value) {
       this.string1 = value;
   }

   public String jsGet_string2() {
       return this.string2;
   }

   public void jsSet_string2(String value) {
       this.string2 = value;
   }

   public String jsGet_string3() {
       return this.string3;
   }

   public void jsSet_string3(String value) {
       this.string3 = value;
   }

   @Override
   public String toString() {
       return id + " " + string1 + " " + string2 + " " + string3;
   }

   @Override
   public String getClassName() {
       return "Person";
   }

   public static Scriptable getInstance(String objectName) throws             IllegalAccessException, InstantiationException, InvocationTargetException  {
       Context jsContext = Context.enter();
       Scriptable person = null;
       try {
           ScriptableObject rootScope = jsContext.initStandardObjects();
           ScriptableObject.defineClass(rootScope, Person.class);
           person = jsContext.newObject(rootScope, "Person", null);
           rootScope.put(objectName, rootScope, person);
       }
       finally {
           Context.exit();
       }
       return person;
   }
}

MyParser类

package com.testpkg;
public class MyParser {    
    public MyParser() {
        System.out.println("Entered MyParser constructor");
    }

    public String PrintObj(ScriptableObject obj) {
        System.out.println("Printing person: " + obj);
        return null;
    }
}

所以当编译执行时如此，

java -cp js.jar;MyParser.jar org.mozilla.javascript.tools.shell.Main TestScript.js

应显示以下输出

Person: jsConstructor
Entered MyParser constructor
Printing person: Person 1 Hello World Another Test

应该注意这里安全地忽略了string4！

Rhino - 无法使用defineClass评估javascript

1 个答案: