如何在Angular.js中为包含的视图定义单独的控制器?

时间:2013-09-01 19:20:18

标签: javascript angularjs

我有两个单独的视图(名为view1.html和view.html),带有单独的控制器(名为controller1和controller2),并使用config路由它们:

myApp.config(['$routeProvider', function($routeProvider) {
    $routeProvider.
    when('/view1', {templateUrl: 'view1.html', controller: controller1}).
    when('/view2', {templateUrl: 'view2.html', controller: controller2}).
    otherwise({redirectTo: '/view1'});
}]);

view1和view2具有模板代码的共享部分,因此我将其提取到新的模板视图(名为view3.html)并在view1.html和view2.html中使用ng-include:

<span ng-view="">
    ...
    <span ng-include="'view3.html'"></span>
    ....
</span>

view3.html逻辑独立于controller1和controller2,因此veiw3.html中所需的范围变量在两个控制器中重复:

function controller1($scope){
    ...
    some code to calculate $scope variables for view3
    ...
}
function controller2($scope){
    ...
    same code to calculate $scope variables for view3
    ...
}

我的问题:有没有办法将控制器中重复的代码提取到view3的单独控制器中?我为view3添加了ng-controller,但它不起作用:

<span ng-controller="controller3">
   view3.html template codes here
</span>

我想这是因为view3.html包含在带有ng-view指令的元素中,并且不能有单独的控制器。

1 个答案:

答案 0 :(得分:0)

我认为您可以使用ng-include来实现它:

在view1.html

<div ng-include src="'view3.html'"></div>
//other template for view1

在view2.html

<div ng-include src="'view3.html'"></div>
//other template for view2

在view3.html

<div ng-controller='controller3'>
    //template for view3
</div>